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3 years ago

A truck travelling at 30m/s decelerates at 1.5m/s². How far does it travel during the 10th second after the brakes are applied?

Physics

1 answer:

11Alexandr11 [23.1K]3 years ago

3 0

Answer

225 meters.

Explanation:

x=x0+30t-(1/2)(1.5)t^2

x=0+30(10)-(1/2)(1.5)(10)^2

x=300-75

x=225

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A water pipe is inclined 40.0° below the horizontal. The radius of the pipe at the upper end is 2.00 cm. If the gauge pressure a

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Answer:

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Explanation:

As it is given that flow rate in the pipe is 20 cm^3/s

so we have

$Q = A_1v_1 = A_2v_2$

at the upper end the area is given as

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Also at the other end

$A_2 = \pi r_2^2$

$A_2 = \pi(0.01)^2 = 0.314 \times 10^{-3} cm^2$

now the speed at two ends is given as

$v_1 = \frac{20}{1.26 \times 10^{-3}}$

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$v_2 = 637 m/s$

now by Bernoulli's theorem we have

$P_1 + \frac{1}{2}\rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2}\rho v_2^2 + \rho g h_2$

now we have

$0.112(1.013 \times 10^5) + \frac{1}{2}1000(159.15)^2 + 1000(9.81)(2.65sin40) = P_2 + \frac{1}{2}(1000)(637)^2 + 0$

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What is the pressure drop due to the bernoulli effect as water goes into a 3.00-cm-diameter nozzle from a 9.00-cm-diameter fire

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Answer:

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Given:

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diameter of nozzle, $d=0.03\ m$

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<u>Now, flow velocity in hose:</u>

$v_h=\frac{\dot V}{\pi.D^2\div 4}$

$v_h=\frac{0.04\times 4}{\pi\times 0.09^2}$

$v_h=6.2876\ m.s^{-1}$

<u>Now, flow velocity in nozzle:</u>

$v_n=\frac{\dot V}{\pi.d^2\div 4}$

$v_n=\frac{0.04\times 4}{\pi\times 0.03^2}$

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$\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}+Z_1=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}+Z_2$

when the two points are at same height then the eq. becomes

$\frac{P_1}{\rho.g}+\frac{v_1^2}{2g}=\frac{P_2}{\rho.g}+\frac{v_2^2}{2g}$

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3 years ago

Andrea and Chuck are riding on a merry-go-round. Andrea rides on a horse at the outer rim of the circular platform, twice as far

velikii [3]

Answer: a) Twice Chuck's

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There exists a relationship between tangential and angular speed, as follows, that relates the definitions of linear and angular speed, and the angle definition:

angle = arc / radius ⇒ Δθ/Δt = Δs/Δt / r ⇒ ω = v/r ⇒ v = ω. r

If ω is constant, v is directly proportional to r, distance to the center (radius in a circular platform), so if r is twice for Andrea, her tangential speed must be twice Chuck's.

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4 years ago

A truck travelling at 30m/s decelerates at 1.5m/s². How far does it travel during the 10th second after the brakes are applied?​

A truck travelling at 30m/s decelerates at 1.5m/s². How far does it travel during the 10th second after the brakes are applied?