Answer:
Second image in your list of possible answers
Explanation:
The second option is what you would expect from modulating a sinusoidal carrier wave of higher frequency after being modulated by a square pulse of lower frequency that allows part of the carrier signal to travel during the time the square signal is constant different from zero, and be absent (flat) during the time the square pulse signal has amplitude zero.
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The answer you are looking for.....
<span>
5.3025kg!</span>
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Answer: Height of building = 17.69m, velocity of brick = 18.6m/s
Explanation: From the question, the body has a zero initial speed, thus initial velocity (u) all through the motion is zero.
By ignoring air resistance makes it a free fall motion thus making it to accelerate constantly with a value of 
.
Time taken to fall = 1.90s
a)
thus the height of the building is calculated using the formulae below
but u = 0 , hence
b)
to get the value of velocity (v) as the brick hits the ground, we use the formulae below
but u= 0, hence
find the attachment in this answer for the accleration- time graph, velocity- time graph and distance time graph
Answer:
acceleraions 5.76g and 20.55g
Explanation:
This constant acceleration exercise can be solved using the kinematic equations in one dimension
Vf = Vo + a t
As part of the rest Vo = 0
a = Vf / t
a = 282/5
a = 56.4 m / s2
In relation to the acceleration of gravity
a ’= a / g = 56.4 / 9.8
a ’= 5.76g
To calculate the acceleration to stop we use the same formula
a2 = 282 / 1.40
a2 = 201.4 m / s2
This acceleration of gravity acceleration function is
a2 ’= 201.4 / 9.8
a2 ’= 20.55g
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