A negative charge is moved from point A to point B along an equipotential surface. Which of the following statements must be tru
1 answer:
Answer:
C) No work is required to move the negative charge from point A to point B.
Explanation:
An equipotential surface is defined as a surface connecting all the points at the same potential.
Therefore, when a charge moves along an equipotential surface, it moves between points at same potential.
The work done when moving a charge is given by
where
q is the charge
is the potential difference between the initial and final point of motion of the charge
However, the charge in this problem moves along an equipotential surface: this means that the potential does not change, so
And so, the work done is also zero.
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Answer:
(1) The maximum air temperature is 1383.002 K
(2) The rate of heat addition is 215.5 kW
Explanation:
T₁ = 17 + 273.15 = 290.15
T₂ = 290.15 × 3.17767 = 922.00139
Therefore,
T₃ = T₂×1.5 = 922.00139 × 1.5 = 1383.002 K
The maximum air temperature = T₃ = 1383.002 K
(2)
Therefore;
Q₁ = 1.005(1383.002 - 922.00139) = 463.306 kJ/jg
Heat rejected per kilogram is given by the following relation;
= 0.718×(511.859 - 290.15) = 159.187 kJ/kg
The efficiency is given by the following relation;
Where:
β = Cut off ratio
Plugging in the values, we get;
Therefore;
Heat supplied =
Therefore, heat supplied = 215491.064 W
Heat supplied ≈ 215.5 kW
The rate of heat addition = 215.5 kW.
The radius of the loop is 18.9 km
Explanation:
When the airplane is at the top of the loop, the pilot experiences two forces:
- The force of gravity, acting downward, of magnitude
- The normal reaction exerted by the seat on the pilot, also acting downward, N
Since the plane is moving in a circular motion, the net force on the pilot must be equal to the centripetal force, therefore we can write:
where
m is the mass of the pilot
is the acceleration of gravity
N is the normal reaction
v = 430 m/s is the speed of the plane
r is the radius of the loop
Here we are told that the pilot feel weightless at the top of the loop: this means that the normal reaction is zero,
N = 0
Therefore the equation becomes
And so we can find the radius of the loop:
Learn more about circular motion:
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