1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Vaselesa [24]
4 years ago
10

A negative charge is moved from point A to point B along an equipotential surface. Which of the following statements must be tru

e for this case? A) The negative charge performs work in moving from point A to point B. B) Work is required to move the negative charge from point A to point B. C) No work is required to move the negative charge from point A to point B. D) The work done on the charge depends on the distance between A and B. E) Work is done in moving the negative charge from point A to point B.
Physics
1 answer:
elena-s [515]4 years ago
7 0

Answer:

C) No work is required to move the negative charge from point A to point B.

Explanation:

An equipotential surface is defined as a surface connecting all the points at the same potential.

Therefore, when a charge moves along an equipotential surface, it moves between points at same potential.

The work done when moving a charge is given by

W=q\Delta V

where

q is the charge

\Delta V is the potential difference between the initial and final point of motion of the charge

However, the charge in this problem moves along an equipotential surface: this means that the potential does not change, so

\Delta V=0

And so, the work done is also zero.

You might be interested in
An electron and a second particle both move in circles perpendicular to a uniformmagnetic field. The mass of the second particle
Katarina [22]

Answer:

The change on the second particle is 2.93\times 10^{-16}\ C.

Explanation:

The period of revolution of the particle in the magnetic field is given by the formula as follows :

T=\dfrac{2\pi m}{Bq}

It is given that the magnetic field is uniform. The mass of the second particle is the same as that of a proton but thecharge of this particle is different from that of a proton.

m_s=m_p

If both particles take the same amount of time to go once around their respective circles. So,

T_e=T_s\\\\\dfrac{2\pi m_e}{Bq_e}=\dfrac{2\pi m_s}{Bq_s}\\\\\dfrac{m_e}{q_e}=\dfrac{m_p}{q_s}\\\\q_s=\dfrac{m_pq_e}{m_e}\\\\q_s=\dfrac{1.67\times 10^{-27}\times 1.6\times 10^{-19}}{9.11\times 10^{-31}}\\\\q_s=2.93\times 10^{-16}\ C

So, the change on the second particle is 2.93\times 10^{-16}\ C.

7 0
3 years ago
Pikes Peak near Denver, Colorado, has an elevation of 14,110 ft. Calculate the pressure at this elevation using three different
kramer

Answer:

a) P = 1240 lb/ft^2

b) P = 1040 lb/ft^2

c) P = 1270 lb/ft^2

Explanation:

Given:

- P_a = 2216.2 lb/ft^2

- β = 0.00357 R/ft

- g = 32.174 ft/s^2

- T_a = 518.7 R

- R = 1716 ft-lb / slug-R

- γ = 0.07647 lb/ft^3

- h = 14,110 ft

Find:

(a) Determine the pressure at this elevation using the standard atmosphere equation.

(b) Determine the pressure assuming the air has a constant specific weight of 0.07647 lb/ft3.

(c) Determine the pressure if the air is assumed to have a constant temperature of 59 oF.

Solution:

- The standard atmospheric equation is expressed as:

                           P = P_a* ( 1 - βh/T_a)^(g / R*β)

                          (g / R*β) = 32.174 / 1716*0.0035 = 5.252

                            P = 2116.2*(1 - 0.0035*14,110/518.7)^5.252

                            P = 1240 lb/ft^2

- The air density method which is expressed as:

                            P = P_a - γ*h

                            P = 2116.2 - 0.07647*14,110

                            P = 1040 lb/ft^2

- Using constant temperature ideal gas approximation:

                            P = P_a* e^ ( -g*h / R*T_a )

                            P = 2116.2* e^ ( -32.174*14110 / 1716*518.7 )

                            P = 1270 lb/ft^2

6 0
3 years ago
Read 2 more answers
Does frequency affect wavelength?
Vinil7 [7]

Answer:

yeah

Explanation:

as wavelength increases frequency decreases and it goes the same for the opposite way

6 0
3 years ago
A 6.0 m section of wire carries a current of 5.2 A from east to west in the earth's magnetic field of 1.0 × 105 T at a location
NNADVOKAT [17]
Well, since you only want direction, ignore the numbers. Use the right hand rule.
Current (pointer finger) points west (left). 
Magnetic field (middle finger) points south (towards you). 
Force (thumb) then points up (away from the earth)
4 0
4 years ago
A 500-n crate needs to be lifted 1 meter vertically in order to get it into the back of a pickup truck. what gives the crate a g
worty [1.4K]
The weight an weight of the truck 
6 0
3 years ago
Read 2 more answers
Other questions:
  • Work is the product of ___<br> _ and an object's displacement.
    15·1 answer
  • Could an experiment similar to young's two-slit experiment be performed with sound? how might this be carried out? does it matte
    10·1 answer
  • Read the scenario and solve these two problems.
    14·2 answers
  • If an upstairs room is warmer than downstairs, is that a example of convection, conduction, or radiation?
    14·1 answer
  • Is it possible for the electric field between two positive charges to equal zero along the line joining the two charges?
    13·1 answer
  • Which statement best describes the difference between how lenses and
    5·2 answers
  • A local AM radio station broadcasts at a frequency of 696 KHz. Calculate the energy of the frequency at which it is broadcasting
    8·1 answer
  • In the diagram, q1= -2.60*10^-9 C and
    10·1 answer
  • A pressure sensor inside of a mixing tank is designed to turn red when the pressure inside the tank exceeds 1.9 kPa. If the sens
    5·1 answer
  • HELP ASAPP!!!! WILL GIVE BRAINLIEST!<br> Describe the chemical structure of a cell membrane
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!