A negative charge is moved from point A to point B along an equipotential surface. Which of the following statements must be tru
1 answer:
Answer:
C) No work is required to move the negative charge from point A to point B.
Explanation:
An equipotential surface is defined as a surface connecting all the points at the same potential.
Therefore, when a charge moves along an equipotential surface, it moves between points at same potential.
The work done when moving a charge is given by
where
q is the charge
is the potential difference between the initial and final point of motion of the charge
However, the charge in this problem moves along an equipotential surface: this means that the potential does not change, so
And so, the work done is also zero.
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Answer:
a)
b)
c)
Explanation:
Before the wire is inserted, the total charge on the inner and outer surface of the cylindrical shell is as follows:
Here, 'h' denotes the length of the cylinder. The total charge of the cylindrical shell is -0.395h μC.
When the thin wire is inserted, the positive charge of the wire attracts the same amount of negative charge on the inner surface of the shell.
a) The new charge on the inner shell is -1.1h μC. Therefore, the new surface charge density of the inner shell can be calculated as follows:
b) The new charge on the outer shell is equal to the total charge minus the inner charge. Therefore, the new charge on the outer shell is +0.705 μC.
The new surface charge density can be calculated as follows:
c) The electric field outside the cylinder can be found by Gauss' Law:
We will draw an imaginary cylindrical shell with radius r > r2. The integral in the left-hand side will be equal to the area of the imaginary surface multiplied by the E-field.
Answer:
Force to stretch the wire is 250 N
Explanation:
As we know that modulus of elasticity will remain the same for the wire if the applied stretch to the wire is within elastic limit
So we will have
now we have
so we can write it as