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Scrat [10]
3 years ago
6

Work out the current through an electric heater with a power of 1.38kW if it uses the 230V mains supply.

Physics
1 answer:
love history [14]3 years ago
5 0

Answer:

I = 6 A

Explanation:

Given that,

Power of an electric heatr, P = 1.38 kW

The voltage of the mains supply, V = 230 V

We need to find the current through the heater. The electric power in terms of  voltage and current is given by :

P=V\times I\\\\I=\dfrac{P}{V}\\\\I=\dfrac{1.38\times 10^3}{230}\\\\I=6\ A

So, the current through an electric heater is 6 A.

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What current flows through a 2.60-cm-diameter rod of pure silicon that is 20.5 cm long, when 1.00 ✕ 103 V is applied to it? (Suc
Virty [35]

Answer:

1.13 mA

Explanation:

Length of wire L = 20.5 cm = 0.205m

Radius of wire r = 2.60/2 = 1.3cm = 0.0130m

Voltage V = 1 × 10³ V

Resistivity of pure silicon p = 2300 Ohms • m

Cross sectional area of the wire

A = pi × r² = pi × (0.013)² = 5.307 × 10 ^-4 m²

Resistance of the material

R = p• L/A

= 2300 • 0.205/5.307 × 10^-4 = 0.888 × 10⁶ Ohms

Using Ohms Law

R = V/ I

I = V/R

I = 10³/0.888 × 10⁶

= 0.001126 A

= 1.13 mA

5 0
4 years ago
Two men decide to use their cars to pull a
joja [24]
The net forward force =(  515 cos 31deg ) +( 926 cos 25 deg )
                                   = 441.44N                + 839.24 N
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3 0
4 years ago
Read 2 more answers
Define second class lever​
Aleks04 [339]

Answer:

Please find detailed explanation of second class levers below

Explanation:

Levers are one of the classes of machine that possesses three levels namely: first class, second class and third claas. A second class lever is the level of levers in which the load (L) is in between the pivot (F) and the effort (E).

Examples of second class levers include; wheelbarrow, a bottle opener etc. In the bottle opener for example, the bottle lid (load) is in between the pivot of the opener and the hand opening it (effort).

6 0
3 years ago
Write a use of magnetic force and frictional force each​
Firdavs [7]
Magnetic force:Computer hard drives use magnetism to store the data on a rotating disk. More complex applications include: televisions, radios, microwave ovens, telephone systems, and computers. ... Frictional force:Quite often uses of friction can be seen from how things would be without friction.
7 0
3 years ago
How much power does an Ox pulling a plow 20 m cross a field, exerting 120J of work over a period of 15 s?​
Aleksandr-060686 [28]

Answer:

8W

Explanation:

Given parameters:

Distance covered  = 20m

Work done  = 120J

Time  = 15s

Unknown:

How much power does the Ox exerts  = ?

Solution:

Power is the rate at which work is being done

  Power  = \frac{Work done }{time}  

 Power exerted by ox  = \frac{120}{15}   = 8W

3 0
3 years ago
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