m(NaOH)=20 g
M(NaOH) = 23+16+1=40 g/mol
20 g*1 mol/40 g= 0.50 mol
0.05 mol NaOH
Answer:
The answer to your question is Qt = 15750 cal
Explanation:
Data
mass = m = 150 g
Initial temperature = T1 = 0°C
Final temperature = T2 = 25°C
Process
1.- Calculate the Latent heat of fusion
Latent heat of fusion for water = l = 80 cal/g
Heat = Q
Formula
Q = ml
Substitution
Q = (150)(80)
Simplification and result
Q = 12000 cal
2.- Calculate the Specific heat
Specific heat of water = C = 1 cal/g°C
Formula
Q = mCΔT
Substitution
Q = (150)(1)(25 - 0)
Simplification and result
Q = 3750 cal
3.- Calculate the total heat
Qt = 12000 + 3750
Qt = 15750 cal
Answer:
B
Explanation:
Water-Continental-Oceanic-Mantle
Answer: The volume of the gas is 1.98 L.
Explanation:
To calculate the final volume of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,
where,
are the initial volume and temperature of the gas.
are the final volume and temperature of the gas.
We are given:
Putting values in above equation, we get:
Thus the volume of the gas is 1.98 L