Answer:
at the beginning: 
pH = 0.745
Explanation:
HCl is a strong acid, so:
        0.18 M             0.18        0.18.....equilibrium
before base is added:
∴ [ H3O+ ] ≅ <em>C </em>HCl = 0.18 M
⇒ pH = - Log [ H3O+ ] = - Log ( 0.18 )
⇒ pH = 0.745
 
        
             
        
        
        
Answer:
I don’t know this answer sorry
Explanation:
 
        
             
        
        
        
Answer:
At -13  , the gas would occupy 1.30L at 210.0 kPa.
 , the gas would occupy 1.30L at 210.0 kPa.
Explanation:
Let's assume the gas behaves ideally.
As amount of gas remains constant in both state therefore in accordance with combined gas law for an ideal gas-
                                           
where  and
 and  are initial and final pressure respectively.
 are initial and final pressure respectively.
             and
  and  are initial and final volume respectively.
 are initial and final volume respectively.
             and
 and  are initial and final temperature in kelvin scale respectively.
 are initial and final temperature in kelvin scale respectively.
Here  ,
 ,  ,
 ,  ,
,  and
 and  
 
Hence    
             
             
             
So at -13  , the gas would occupy 1.30L at 210.0 kPa.
 , the gas would occupy 1.30L at 210.0 kPa.
 
        
             
        
        
        
Answer:
Copper
Explanation:
Within intermolecular forces, ion-dipole is the strongest, followed by hydrogen bonding, then dipole-dipole, and then London dispersion.
 
        
             
        
        
        
Answer:
The element that glows in signs is xenon.
Explanation:
Xenon is a chemical element with the symbol Xe and atomic number 54. It is a colorless, dense, odorless noble gas found in Earth's atmosphere in trace amounts. Xenon is used in flash lamps, arc lamps, and as a general anesthetic. Xenon emits a blue or lavenderish glow when excited by electrical discharge, it emits a band of emission lines that span the visual spectrum, but the most intense lines occur in the region of blue light, producing the coloration.