Formula for terminal
velocity is:
Vt = √(2mg/ρACd)
<span>Vt = terminal velocity = ?
<span>m = mass of the falling object = 72 kg
<span>g = gravitational acceleration = 9.81 m/s^2
<span>Cd = drag coefficient = 0.80
<span>ρ = density of the fluid/gas = 1.2 kg/m^3</span>
<span>A = projected area of the object (feet first) = 0.21 m * 0.41
m = 0.0861 m^2
Therefore:</span></span></span></span></span>
Vt = √(2 * 72
* 9.81 / 1.2 * 0.0861 * 0.80)
<span>Vt = 130.73 m/s</span>
Answer:
Explanation:
The formula that you are working with is F = m*a
Since mass is one part of the formula if you increase the mass, you are going to increase the force.
The second one is much more difficult to answer because it is basically incomplete. This is one way to interpret it. If you start at a certain speed and increase during a known time period then effectively you are defining acceleration which is "a" in the formula.
Without those modifications, there is no answer.
Answer:
the bending moment will be W from either sides
Explanation:
bending moment= force (load) * perpendicular distance, if I understand the question the distance will be 1/2 of the length
=> f x 1/2(l) =W*1/2(2) =W
Answer: It prevents us from seeing most of the galactic disk with visible and ultraviolet light.
(hope this helps) :)
The shadow that will be protected on the ground will represent the hawk's horizontal position. therefore it will move at the hawk's horizontal velocity component, which is:
5*cos(60) = 2.5 m/s
