Answer:
Explanation:
A.the direction of induced current will be clockwise
B: Changing 18cm and 6.8cm into 0.18m and 0.68
2.5
Divide them both by 2 to find the radius . Now we have 0.09 and .034m.
Now use Φ=(π*0.09^2)(.75 T)cos0 and the 0.019wb
(π*0.034^2)(.75 T)cos0 and the 0.00272wb
ow use ε=-N(ΔΦ/Δt)
For ΔΦ, 0.091-0.0027=0.0883
C.
To find the current, use I=ε/R
0.0883/2.5= 0.035A
Answer: A
Explanation: the lower the time, the faster you complete the race ( i also had this question before)
Answer:
A) 15.0 years
Explanation:
Due to the distance to the star system is in light-year units, we can compute the time by using:

then, Rob will take to complete the trip about 15 light-years.
hope this helps!!
Answer:5
Explanation:
Given
First Plate has a charge of +Q and area A
Second Plate has a charge of -3 Q and area A
We Know electric Field due to sheet charge is given by

Where Q=charge over the Plate
A=Area of plate
= Permittivity of free space
Electric Field Due to Positive charge will always be away from it while for negative charge it is towards it.
Net Electric Field at a point between between the Plates is the superimposition of two electric with direction


Net electric Field is towards the negative charged plate
Well first of all, when it comes to orbits of the planets around
the sun, there's no such thing as "orbital paths", in the sense
of definite ("quantized") distances that the planets can occupy
but not in between. That's the case with the electrons in an atom,
but a planet's orbit can be any old distance from the sun at all.
If Mercury, or any planet, were somehow moved to an orbit closer
to the sun, then ...
-- its speed in orbit would be greater,
-- the distance around its orbit would be shorter,
-- its orbital period ("year") would be shorter,
-- the temperature everywhere on its surface would be higher,
-- if it has an atmosphere now, then its atmosphere would become
less dense, and might soon disappear entirely,
-- the intensity of x-rays, charged particles, and other forms of
solar radiation arriving at its surface would be greater.