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3 years ago

Explain why clouds are generally observed to form only in the troposphere?

Chemistry

2 answers:

Paul [167]3 years ago

8 0

Answer:

because we bystanders can see them through the sky and from the ground.

Explanation:

pls give brainliest im almost lvled up.

laila [671]3 years ago

7 0

Answer:

Air pressure and the density of the air are also less at high altitudes. The layer above the troposphere is called the stratosphere. Nearly all of the water vapor and dust particles in the atmosphere are in the troposphere. That is why most clouds are found in this lowest layer, too.

Explanation:

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Standard Thermodynamic Quantities for Selected Substances at 25 ∘C Reactant or product ΔHf∘(kJ/mol) Al(s) 0.0 MnO2(s) −520.0 Al2

Svet_ta [14]

Answer:

-1815.4 kJ/mol

Explanation:

Starting with standard enthalpies of formation you can calculate the standard enthalpy for the reaction doing this simple calculation:

∑ n *ΔH formation (products) - ∑ n *ΔH formation (reagents)

This is possible because enthalpy is state function meaning it only deppends on the initial and final state of the system (That's why is also possible to "mix" reactions with Hess Law to determine the enthalpy of a new reaction). Also the enthalpy of formation is the heat required to form the compound from pure elements, then products are just atoms of reagents organized in a different form.

In this case:

ΔH rxn = [(2 * -1675.7) - (3 * -520.0)] kJ/mol = -1815.4 kJ/mol

4 0

3 years ago

What is the change in internal energy (ΔΕ) of a system when 5 kJ of work is done on the system while it releases 13 kJ of energy

meriva

The change in internal energy (ΔΕ) of a system : -8 kJ

<h3>Further explanation </h3>

The laws of thermodynamics 1 state that: energy can be changed but cannot be destroyed or created

The equation is:

$\tt \Delta U=Q+W$

Energy owned by the system is expressed as internal energy (U)

This internal energy can change if it absorbs heat Q (U> 0), or releases heat (U <0). Or the internal energy can change if the system does work or accepts work (W)

The sign rules for heat and work are set as follows:

• The system receives heat, Q +

• The system releases heat, Q -

• The system does work, W -

• the system accepts work, W +

5 kJ of work is done on the system : W = +5 kJ

releases 13 kJ of energy to the surroundings : Q = -13 kJ

$\tt \Delta E=-13+5=-8~kJ$

6 0

3 years ago

Explain why there would be a need for lithium batteries?

Leviafan [203]

Answer:

The much higher power density offered by lithium ion batteries is a distinct advantage. Electric vehicles also need a battery technology that has a high energy density. ... Lithium ion cells is that their rate of self-discharge is much lower than that of other rechargeable cells such as Ni-Cad and NiMH forms.

Put this into your own words or teachers will make you redo it

6 0

3 years ago

A 2.684-g sample of zinc oxide was reduced by hydrogen gas, resulting in 2. 156 g of pure zinc metal. Determine the empirical fo

Afina-wow [57]

The empirical formula of the initial zinc oxide is ZnO.

<h3>What is Empirical Formula?</h3>

The empirical formula of a compound represents the ratios of elements in a compound but not the actual numbers or arrangement of the atoms.

It is the lowest whole number ratio of the element in the compound.

<h3>How to find out the empirical formula?</h3>

Find out the given masses and molar masses of the elements

The molar mass of Zn = 65 gmol⁻¹

Given the mass of Zn = 2.156 g

The molar mass of Oxygen = 16 gmol⁻¹

The mass of Oxygen = Mass of a sample of zinc oxide - the mass of zinc metal

= (2.684 - 2.156) g

= 0.528 g

Find the number of moles of the elements in the compound

The number of moles is given by

$n = \frac{m}{M}$

where m = given mass and

M = Molar mass

Number of moles of Zinc = $\frac{2.156}{65}$ = 0.033 moles

Number of moles of Oxygen = $\frac{0.528}{16}$ = 0.033 moles

Find the simplest ratios of the elements in the compound. To find the ratios simply divide the number of moles by the lowest number of moles obtained.

Here, the number of moles is the same for both elements. Hence, the simplest ratio for Zn:O is 1:1.

Therefore, the empirical formula of zinc oxide is ZnO.

Learn more about the empirical formula:

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5 0

1 year ago

A sample of substance X that has a mass of 326. 0 g releases 4325. 8 cal when it freezes at its freezing point. If substance X h

solmaris [256]

The molar heat of fusion of X has been 775.6 cal/mol. Thus, option C is correct.

The molar heat of fusion has been defined as the energy absorbed or released by a mole of substance in converting between solid and liquid state.

<h3>Computation for the molar heat of fusion</h3>

The given mass of substance X has been, 326 g.

The molar mass of substance X has been 58.45 g/mol.

The moles of sample have been given as:

$\rm Moles=\dfrac{Mass}{Molar\;mass}\\\\ Moles\;X=\dfrac{326\;g}{58.45\;g/mol}\\\\ Moles\;X=5.58\;mol$

Thus, the amount of heat absorbed by 5.58 mol of sample has been 4325.8 cal.

The amount of heat absorbed by a mole of sample has been:

$\rm 5.58\;mol=4325.8\;cal\\\\1\;mol=\dfrac{4325.8\;cal}{5.58\mol} \\\\1\;mol=775.6\;cal/mol$

The amount of heat absorbed by a mole of sample in meting has been the molar heat of fusion.

Thus, the molar heat of fusion of X has been 775.6 cal/mol. Thus, option C is correct.

Learn more about heat of fusion, here:

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3 0

2 years ago