Processing Questions:

Suppose a woman raises a 65 N object in 2m in 4 seconds.

Novosadov [1.4K]

Answer:

$\huge\boxed{\sf P.E = 130\ Joules}$

$\huge\boxed{\sf P = 32.5\ Watts}$

Explanation:

Given Data:

Weight = W = 65 N

Height = h = 2 m

Time = t = 4 secs

Required:

Power = P = ?

Work Done in the form of Potential Energy = P.E. = ?

Formula:

P.E. = Wh

P = P.E. / t

Solution:

P.E. = (65)(2)

P.E = 130 Joules

P = P.E. / t

P = 130 / 4

P = 32.5 Watts

$\rule[225]{225}{2}$

Hope this helped!

8 0

2 years ago

A person's body is producing energy internally due to metabolic processes. If the body loses more energy than metabolic processe

SVETLANKA909090 [29]

Answer:

$T_s = 6.8 degree C$

Explanation:

As per thermal radiation we know that rate is heat radiation is given as

$\frac{dQ}{dt} = \sigma eA (T^4 - T_s^4)$

here we know that

T = 34 degree C = 307 K

$A = 1.38 m^2$

e = 0.557

$\sigma = 5.67 \times 10^{-8} W/m^2K^4$

$\frac{dQ}{dt} = 120 J/s$

now we have

$120 = (5.67 \times 10^{-8})(0.557)(1.38)(307^4 - T_s^4)$

$120 = (4.36 \times 10^{-8})(307^4 - T_s^4)$

$T_s = 279.8 K$

$T_s = 6.8 degree C$

5 0

3 years ago

In which scenario is an animal doing work? Check all that apply.

AleksAgata [21]

Answer:

I think the letter B is a good idea for me to do the same as oneroure oneroure I I was just wondering if you could give me a a little more about what you are looking for in a career in the area of the main crop between the rows of the main crop between the rows of the main crop between the between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop main crop between the between the rows of rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between the rows of the main crop between a single one or more and then you have the right one for your hair that fits your hair and you are not the one to choose from the given choice of the following proof choose your own style or the color of your a color scheme that is used in used color and colors and colors of your company name what you want and how you can easily find the perfect fit in a wide range of colors the colors colors you choose want for the following elements to make sure your style is style fits into your design or and how your design is design in your style style design and color style design and color style design design and style design for your wedding photography studio design and photography studio design studio photography gallery featuring a wide web design gallery and photo design gallery design and design gallery and photo design and design studio photography studio design and photography studio photography photography photography photography photography gallery photography photography photography studio wedding photography wedding photography wedding photography wedding photography wedding photography wedding photography wedding photography wedding photography wedding photography wedding photography wedding photography wedding photography wedding photography wedding photography wedding photography wedding photography wedding wedding photography

6 0

2 years ago

Help pleasessssssssssssss

irinina [24]

Sorry I had the answer but it wont let me type numbers :(.:

5 0

2 years ago

Two carts, A and B, are connected by a spring and sitting at rest on a track. Cart A has a mass of 0.4 kg and Cart B has a mass

Ilya [14]

Both carts experience the same force but Cart A has a greater speed after the recoil.

The given parameters;

Mass of the cart A = 0.4 kg
Mass of the cart B = 0.8 kg

Apply the principle of conservation of linear momentum to determine the velocity of the carts after collision;

$m_Av_0_A\ + m_Bv_0_B = m_Av_f_A \ + m_Bv_f_B\\\\the \ initial \ velocity \ of \ both \ carts = 0\\\\0.4(0) + 0.8(0) = 0.4v_f_A + 0.8v_f_B\\\\0 = 0.4v_f_A + 0.8v_f_B\\\\0.4v_f_A = -0.8v_f_B\\\\v_f_A= \frac{-0.8 v_f_B}{0.4} \\\\v_f_A = - 2 \ v_f_B \ \ m/s$

According to Newton's third law of motion, action and reaction are equal and opposite. The force exerted on cart A is equal to the force exerted on cart B but in opposite direction.

$F_A = -F_B$

Thus, the correct statement that compares the motion and forces acting on the two carts is "Both carts experience the same force but Cart A has a greater speed after the recoil."

Learn more about conservation of linear momentum here: brainly.com/question/7538238

6 0

2 years ago