Data:
Explanation:
The rate constant as a function of the temperature can be expressed using the Arrhenius equation, as follows,
Then, find a value for the constant A, according to the data given in the exercise,
As the rate constant has units then, the reaction corresponds to one of first order. Then, the reaction corresponds to:
Which tell the amount of mass (mol) is produced by second per unity of volume.
Answer:
If the reaction goes twice fast, the reaction rate corresponds to,
The expression above can be reduced to:
Replacing k(T) in order to obtain the temperature T,
Replacing all values,
Answer:
2,8,8
when Ca gives out 2 electrons it is deducted from it's electronic configuration in it normal state
I uploaded the answer to a file hosting. Here's link:
tinyurl.com/wpazsebu
The given question is incomplete. The complete question is :
The thermal decomposition of phosphine (PH3) into phosphorus and molecular hydrogen is a first-order reaction: The half-life of the reaction is 35.0 s at 680°C. Calculate the first order rate constant.
Answer: a) The first order rate constant is
b) The time after which 95% reactions gets completed is 151 seconds
Explanation:
Expression for rate law for first order kinetics is given by:
where,
k = rate constant
t = age of sample
a = let initial amount of the reactant
a - x = amount left after decay process
a) for finding the rate constant
Half life is the amount of time taken by a radioactive material to decay to half of its original value.
The first order rate constant is
b) for completion of 95 % of reaction
The time after which 95% reactions gets completed is 151 seconds
Answer:
a. +2
b. +3
c. -1
Explanation:
The typical oxidation states can be determined from the periodic table based on the number of valence electrons an atom has.
a. Calcium belongs to group 2A, meaning it has 2 valence electrons and, therefore, would have an oxidation state of +2 in compounds.
b. Aluminum is in group 3A, meaning it has 3 valence electrons and would have an oxidation state of +3 in compounds when the 3 electrons are lost.
c. Fluorine would become fluorine if it gained 1 additional electron to achieve an octet, so its oxidation state would be -1.