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3 years ago

Given the reaction: HSO4– + HPO42– ↔ SO42– + H2PO4-Which pair represents an acid and its conjugate base?

1 answer:

6 0

Hello!

The pair which represents an acid and its conjugate base is HSO₄⁻ and SO₄⁻².

To know if a pair of substances represents an acid and its conjugate base, one should look at the chemical structure of each substance. The conjugate base of an acid has usually the same chemical formula than the acid, but with one less proton (H⁺). Of the pairs of substances on the list, only HSO₄⁻ and SO₄⁻² have similar structures, with the only difference being the number of protons. The chemical reaction of dissociation of HSO₄⁻ is the following:

HSO₄⁻ + H₂O ⇄ SO₄⁻² + H₃O⁺

Have a nice day!

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What makes an atom able to form a compound? * O different number of neutron than protons O unfilled outer electron shells O same

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Answer:

same number of protons as electrons

Explanation:

The addition of a neutron can make an atom radioactive. When you change the number of protons in an atom, you will change the atom from one element to a different element. ... If you change the number of electrons in an atom, you will get an ion of the element.

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3 years ago

The hcl(g) molecule has a bond length of 127 pm and a dipole moment of 1.08

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Let us assume that this molecule is 100 percent ionic. In that case, the charges are distinguished by a bond length.

h = Q × r

= (160 × 10⁻¹⁹ c) (127 × 10⁻¹² m) (10 / 3.336 × 10⁻³⁰ cm)

= 6.09 D.

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= 1.08 D / 6.09 D × 100

= 17.7 %.

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3 years ago

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4 years ago

Read 2 more answers

2 C6H14 + 19 O2 --> 12 CO2 + 14 H2O

Rashid [163]

Answer:

4.06 mol H₂O

Explanation:

2C₆H₁₄ + 19O₂ → 12CO₂ + 14H₂O

First we convert the given masses of reactants into moles, using their respective molar masses:

250 g O₂ ÷ 32 g/mol = 7.81 mol O₂

50 g C₆H₁₄ ÷ 86 g/mol = 0.58 mol C₆H₁₄

Now we calculate how many O₂ moles would react completely with 0.58 C₆H₁₄ moles, using the stoichiometric coefficients of the reaction:

0.58 mol C₆H₁₄ * $\frac{19molO_2}{2molC_6H_{14}}$ = 5.51 mol O₂

As there are more O₂ moles than required (7.81 vs 5.51), O₂ is the reactant in excess. That means that C₆H₁₄ is the limiting reactant.

Now we can calculate how much water can be formed, using the number of moles of the limiting reactant:

0.58 mol C₆H₁₄ * $\frac{14molH_2O}{2molC_6H_{14}}$ = 4.06 mol H₂O

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3 years ago

A flame test of a colorless solution gives a bright yellow color. When reacted with AgNO3 a white precipitate forms that dissolv

hichkok12 [17]

Answer:

The compound is Na2CO3

Explanation:

A flame test of a colorless solution gives a bright yellow color. The yellow color shows the presence of Sodium.

NaX + AgNO3 → AgX + NaNO3

When reacted with AgNO3 a white precipitate.

AgX + HNO3 → AgNO3 + H2O + CO2

A white precipitate will be formed when AgNO3 reacts with Sodium Chloride (NaCl) or Sodium carbonate(Na2CO3). (Also NaF, Na3PO4 are possible).

When HCL is added to the unknown solution, bubbles form.

Forming bubbles means that there is formed CO2 (and H20)

Na2X + 2HCl → 2NaCl + H2O + CO2

To form CO2 there is carbon needed

This shows that X is CO3 and the compound is Na2CO3

To control:

Na2CO3 + AgNO3 → Ag2CO3 + NaNO3

⇒Ag2Co3 is the white precipitate formed

This precipitate Ag2CO3 + HNO3 will disolve in AgNO3, CO2 and H2O

When Na2CO3 reacts with HCl there is formed NaCL together with bubbles ( which is CO2 and H2O).

The compound is Na2CO3

3 0

4 years ago