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pickupchik [31]
3 years ago
15

You are a support technician working in a data closet in a remote office. You suspect that a connectivity problem is related to

a broken RJ-45 plug on a patch cable that connects a switch to a patch panel. You need to replace that connector, but you forgot to bring an extra patch cable. You decide to install a new RJ-45 connector to replace the broken connector. Which tools must you have in order to successfully accomplish this task?
Physics
1 answer:
Nostrana [21]3 years ago
5 0

Answer:

crimping tool

Explanation:

This is a tool employed in affixing a connector to the end of a network cable.

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vfiekz [6]

Answer:

forever

Explanation:

6 0
3 years ago
Read 2 more answers
You hear a sound with a frequency of 256 Hz. The amplitude of the sound increases and decreases periodically: it takes 2 seconds
german

To solve this problem it is necessary to take into account the concepts related to frequency and period, and how they are related to each other.

The relationship that defines both agreements is given by the equation,

f_{beat}=\frac{1}{T}

Then the frequency for the previous period given (2sec) is

f_{beat}=\frac{1}{2}

f_{beat} = 0.5Hz

The beat frequency of two frequencies is equal to the difference between the two frequencies, then

f_{beat} = |f_1-f_2|\\f_{beat} = |256Hz-2Hz|\\f_{beat} = 254Hz

<em>Hence option A is incorrect.</em>

We can do this process for 254Hz as f_1 and 258 Hz for f_2 , then

f_{beat} =|254Hz-258Hz|

f_{beat} = 4Hz

<em>Hence option B is incorrect. </em>

We can also do this process for 255Hz as  f_1 and 257 Hz for f_2 , then

f_{beat} =|255Hz-257Hz|

f_{beat} = 2Hz

<em>Hence option C is incorrect. </em>

We can also do this process for 255.5Hz as f_1 and 256.5 Hz for f_2, then

f_{beat} =|255.5Hz-256.5Hz|\\f_{beat} = 1Hz

<em>Hence option D is incorrect. </em>

We can also do this process for 255.75Hz as f_1 and 256.25 Hz for f_2, then

f_{beat} =|255.75Hz-256.25Hz|\\f_{beat} = 0.5Hz

<em>Hence option E is incorrect. </em>

Therefore the sum of the frequencies in the sound wave would be 256.25Hz and 255.75Hz

3 0
3 years ago
Why is it important to use placebos and a double-blind approach in some studies
viktelen [127]
Another name for these two words is "constant" and you want to have a "constant", because you want something to compare your experimental group to, to see whether data had changed or not. So you have placebos or a double- blind to compare your experimental group to it and also so you know you don't have a bias or anything in the study.
6 0
2 years ago
4025.05m +20.0m +0.050004m
PIT_PIT [208]
The answer is 4,045.1 meters
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3 years ago
The accompanying map shows the route traveled by a school bus.
Shtirlitz [24]

Answer:

C

Explanation:

6 0
3 years ago
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