The density is 15.23 g/cm^3
Answer:
Since asexual reproduction essentially makes clones of the parent bacterium, the daughter bacterium will behave and react exactly the same as the parent.
Answer:
V₂ = 6.14 L
Explanation:
Given data:
Initial volume = 9.5 L
Initial pressure = 1.02 atm
Initial temperature = 20.1 °C (20.1 +273 = 293.1 K)
Final temperature = 15°C (15+273 = 288 K)
Final volume = ?
Final pressure = 1.55 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂/T₁ P₂
V₂ = 1.02 atm × 9.50 L × 288 K / 293.1 K × 1.55 atm
V₂ = 2790.72 atm. L.K / 454.305 K. atm
V₂ = 6.14 L
When temperatures rise, the body reacts by increasing blood flow to the skin's surface, taking the heat from within the body to the surface. This means sweat. ... If, as in the UK, our skin temperature is warmer than the external temperature we are also able to lose heat to the environment, termed 'dry heat loss'.
The heat required to increase the temperature of 1.20 g of water is 80,256 k/j
<h3>What is specific heat?</h3>
The amount of energy needed to raise the temperature of one gram of a substance by one degree Celsius.
4. 18 J heat is required to change the temperature of 1.20 kg of water from 23. 00 °c to 39. 00 °c.
The heat required to raise temperature is the product of mass, specific heat and temperature change
1,200 × 4.18 × (39 − 23) = 80,256
Thus, the heat required to increase the temperature of 1.20 g of water is 80,256 k/j
Learn more about specific heat
brainly.com/question/11297584
#SPJ4