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Umnica [9.8K]
3 years ago
12

when a chemical change occurs, if the temperature drops, what effect will it have on the rate of chemical reaction?

Chemistry
1 answer:
Nikolay [14]3 years ago
6 0

Answer:

the rate of reaction would decrease

Explanation:

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What is the pressure if 0.567 moles of gas occupy 4.5 liters at a temperature of 300.0 K?
kakasveta [241]
The answer is D. Use the equation PV=nRT
P=(.567mol)(.0821)(300K)/4.5L
3 0
3 years ago
1. write the complete chemical symbol for the ion with 14 protons 15 neutrons and 18 electrons
motikmotik

Answer:

1.   Si^{-4}

2.  Co^{+2}

Explanation:

An ion is formed when an atom that is said to be neutral gains or losses electrons.

It is thought that a negative ion (anion) is produced as it gains electrons and a positive ion (cation) is formed when it loses an electron.

Atomic number is the total number of protons and electrons in a neutral atom.

From the information

Protons = 14

electron = 18

Net Charge = no of proton - no of electron

= 14 - 18 = -4

Mass number = 14 + 15 = 29

Thus, the chemical symbol = Si^{-4}

For ion with 27 proton, 32 neutrons and 25 electrons

Net charge = 27 - 25 = +2

Mass number = 27 + 32 = 59

Thus, the chemical symbol = Co^{+2}

6 0
3 years ago
An atom is described as a nucleus of protons and neutrons surrounded by a(n)
abruzzese [7]
(C) Electron cloud

the electron cloud is formed by all the electrons in the atom
8 0
3 years ago
Read 2 more answers
Which of the following isotopes is radioactive A)C-12 B)Pb-206 C) Tc-99 D)Ne-20
Gre4nikov [31]
C) Tc-99 is a radioactive isotope also known as radioisoptope. 
4 0
3 years ago
A certain radioactive nuclide has a half life of 1.00 hour(s). Calculate the rate constant for this nuclide. s-1 Calculate the d
Karo-lina-s [1.5K]

Answer:

k= 1.925×10^-4 s^-1

1.2 ×10^20 atoms/s

Explanation:

From the information provided;

t1/2=Half life= 1.00 hour or 3600 seconds

Then;

t1/2= 0.693/k

Where k= rate constant

k= 0.693/t1/2 = 0.693/3600

k= 1.925×10^-4 s^-1

Since 1 mole of the nuclide contains 6.02×10^23 atoms

Rate of decay= rate constant × number of atoms

Rate of decay = 1.925×10^-4 s^-1 ×6.02×10^23 atoms

Rate of decay= 1.2 ×10^20 atoms/s

8 0
3 years ago
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