Answer:
Rod will remain horizontal all the time after release.
Explanation:
This is because net torque on the rod about any point in space is zero.
Let assume that distance between the two masses m and 2m is L.
Also m is situated at origin and in positive XY direction.
Then , Center of mass is at L()
COM =
So let us calculate net torque about hinged point which COM.
- Torque because of hinge force is zero because it passes from that point itself.
- Torque on 2m mass is 2mg(L/3) in nenegative Z direction.
- Torque on m mass is mg(2L/3) in positive Z direction.
As both torque are equal and opposite then net torque =0.
Thus it got balanced.
The Earth's orbital period change is A: It would increase by 0.15 years
Using Kepler's third law which states that the square of the orbital period of the planet is directly proportional to the cube of its distance from the sun.
So, T² ∝ R³
T'²/T² = R'³/R³ where
- T = orbital period at R = 1 year
- R = initial axis length = 1 AU
- T' = orbital period at R'
- R' = final axis length = 1.1 AU.
So, making T' subject of the formula, we have
T' = [√(R'/R)³]T
T' = [√(1.1 AU/1 AU)³] × 1 year
T' = [√(1.1)³] × 1 year
T' = √1.331 × 1 year
T' = 1.15 × 1 year
T' = 1.15 years.
So, the change in the Earth's orbital period ΔT = T' - T
= 1.15 years - 1 year
= 0.15 years
Since this is positive, the orbital period <u>increases</u> by 0.15 years.
So, the Earth's orbital period change is A: It would increase by 0.15 years
Learn more about Kepler's third law here:
brainly.com/question/16546004
Answer: M^-1 L^-3T^4A^2
Explanation:
From coloumb's law
K = q1q2 / (F × r^2)
Where;
q1, q2 = charges
k = constant (permittivity of free space)
r = distance
Charge (q) = current(A) × time(T) = TA
THEREFORE,
q1q2 = (TA) × (TA) = (TA)^2
Velocity = Distance(L) / time(T) = L/T
Acceleration = change in Velocity(L/T) / time (T)
Therefore, acceleration = LT^-2
Force(F) = Mass(M) × acceleration (LT^-2)
Force(F) = MLT^-2
Distance(r^2) = L^2
From ; K = q1q2 / (F × r^2)
K = (TA)^2 / (MLT^-2) (L^2)
K = T^2A^2M^-1L^-1T^2 L^-2
COLLEXTING LIKE TERMS
T^2+2 A^2 M^-1 L^-1-2
M^-1 L^-3T^4A^2
Answer:
The distance between two objects
Explanation:
Depending on how far away or how close two objects are will affect the gravity.