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Scrat [10]
3 years ago
8

When a small amount of hydrogen gas mixes with nitrogen gas, hydrogen is the

Chemistry
1 answer:
Verdich [7]3 years ago
4 0

Answer:

solvent

Explanation:

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Help balance (will mark brainliest)
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An endothermic process is one in which heat is ________ from the surroundings. (2 points)
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Always <span><span>think "into" for "endo" (energy goes in), and "exit" for "exo" (energy is released).</span> </span>

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3 years ago
A flash distillation chamber operating at 101.3 kpa is separating an ethanol water mixture the feed mixture contains z weight et
Alex73 [517]

Answer:

The answer is [\frac{LX_1}{46} + \frac{L(1-x)}{18}]\times0.454 mol/hr

[\frac{Vy_1}{46}+\frac{V(1-y)}{18}]\times0.454mol/hr

Explanation:

For flash distillation

F = V+L

\frac{V}{F} + \frac{L}{F} = 1

\frac{F}{V} -\frac{L}{V} = 1

Fz = Vy+Lx

Y = \frac{F}{V}\times Z - \frac{L}{V}\times X                  let, \frac{V}{F} = F

y = \frac{Z}{F} -[ \frac{1}{F} -1]\times X

Highlighted reading

F = 299;  \frac{V}{F} = 0.85 ; z = 0.36

y = \frac{0.36}{0.85} - (-0.15)\times X

 = 0.423 + 0.15x ------------(i)

y^{*} = -43.99713x^{6} + 148.27274x^{5} - 195.46x^{4}+127.99x^{3}-43.3x^{2}+ 7.469x^{}+ 0.02011

At equilibrium, y^{*} = y

0.423+0.15x^{} = y^{*}

-43.99713x^{6}+ 148.27274x^{5} - 195.46x^{4}+127.99x^{3}-43.3x^{2}+ 7.319x^{}-0.403

F(x) for Newton's Law

Let x_{0} = 0

     x_{1}     = \frac{0-[{-0.403}]}{7.319}

             = 0.055

     x_{2}      = \frac{{0.055}-{f(0.055)} {{{{{{{}}}}}}}}{f^{'} (0.055)}

             = \frac{{(0.055)}-(-0.11)}{3.59}

             = 0.085

    x^{3}    = \frac{{0.085}-(0.024)}{2.289}

           = 0.095

   x^{4}     = \frac{{0.095}-(-0.0353)}{-1.410}

            = 0.07

From This x and y are found from equation (i) and L and V are obtained from \frac{V}{F}  and F values

[\frac{LX_1}{46} + \frac{L(1-x)}{18}]\times0.454 mol/hr

[\frac{Vy_1}{46}+\frac{V(1-y)}{18}]\times0.454mol/hr

   

8 0
3 years ago
The combustion of magnesium creates so much energy so quickly that it is hard to measure its enthalpy directly using a simple ca
vlabodo [156]

Answer:

sorrrrrrrrrry

Explanation:

6 0
3 years ago
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