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Evgen [1.6K]
3 years ago
15

The Independent Variable is: Kinetic Energy Height Mass Speed

Chemistry
2 answers:
brilliants [131]3 years ago
6 0
The correct answer is height
GenaCL600 [577]3 years ago
4 0
The independent variable is height
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If the a of a monoprotic weak acid is 2. 6×10−6, what is the ph of a 0. 33 m solution of this acid?
yawa3891 [41]

The pH of the monoprotic weak acid is 2.79.

<h3>What are weak acids?</h3>

The weak acids are the acids that do not fully dissociate into ions in the solution. Strong acids fully dissociate into ions.

The chemical reaction is HA(aq) ⇄ A⁻(aq) + H⁺(aq).

c (monoprotic acid) = 0.33 M.

Ka = 1.2·10⁻⁶

[A⁻] = [H⁺] = x

[HA] = 0.33 M - x

Ka = [A⁻]·[H⁺] / [HA]

2. 6 × 10⁻⁶ = x² / (0.33 M - x)

Solve quadratic equation: [H⁺] = 0.000524 M.

pH = -log[H⁺]

pH = -log(0.000524 M)

pH = 2.79

Thus,  the pH of the monoprotic weak acid is 2.79

To learn more about weak acids, refer to the below link:

brainly.com/question/13032224

#SPJ4

5 0
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Which of the following ion is the least and the most hydrated? OH- , Li+, K+, Na+​
vodomira [7]
I don’t know either lol
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Why is the process of nuclear fusion important to life on Earth?
GrogVix [38]
Nearly all life on Earth gets its energy from the sun, and the sun gets its energy through the process of nuclear fusion, which is why these type of energy is important to life on Earth.
6 0
3 years ago
At 1.00 atmosphere pressure, a certain mass of a gas has a temperature of 100oC. What will be the temperature at 1.13 atmosphere
Inessa [10]

Answer:  Final temperature of the gas will be 330 K.

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

P\propto T     (At constant volume and number of moles)

{P_1\times T_1}={P_2\times T_2}

where,

P_1 = initial pressure of gas   = 1.00 atm

P_2 = final pressure of gas  = 1.13 atm

T_1 = initial temperature of gas  = 100^0C=(100+273)K=373K K

T_2 = final temperature of gas  = ?

{1.00\times 373}={1.13\times T_2}

T_2=330K

Therefore, the final temperature of the gas will be 330 K.

7 0
3 years ago
Which letter is closest to the warm front, and which is closest to the cold front
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