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3 years ago

Please help me!!!

Chemistry

1 answer:

V125BC [204]3 years ago

3 0

Answer:

solid to liquid i think

Explanation:

entropy is natural disorder in simple terms- liquid the atoms are less organised than in a solid to increased entropy as they move apart becoming disordered

at least this is how i understand it

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Consider the substitution reaction that rakes place when (R)-3-bromo 3-methylhexane is treated with methanol. Which of the follo

Otrada [13]

Answer:

The reaction would take place with racemization.

Explanation:

The compound (R)-3-bromo 3-methylhexane contains has the leaving group attached to a tertiary carbon atom. When the leaving group is attached to a tertiary carbon atom, the compound undergoes nucleophilic substitution via SN1 mechanism. This mechanism involves the formation of a planar carbocation intermediate. The nucleophile may attack this intermediate from either faces, leading to racemization of the product.

5 0

3 years ago

Which type of bond does this molecule show?

Gekata [30.6K]

The correct answer is D. magnetic bond

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2 years ago

What is the calculated value of the cell potential at 298K for an

Tpy6a [65]

The question is incomplete, here is the complete question:

What is the calculated value of the cell potential at 298 K for an electrochemical cell with the following reaction, when the H₂ pressure is 6.56 x 10⁻² atm, the H⁺ concentration is 1.39 M, and the Sn²⁺ concentration is 9.35 x 10⁻⁴ M?

$2H^+(aq)+Sn(s)\rightarrow H_2(g)+Sn^{2+}(aq)$

Answer: The cell potential of the given electrochemical cell is 0.273 V

Explanation:

For the given chemical equation:

$2H^+(aq)+Sn(s)\rightarrow H_2(g)+Sn^{2+}(aq)$

The half cell reactions for the given equation follows:

Oxidation half reaction: $Sn(s)\rightarrow Sn^{2+}(aq)+2e^-;E^o_{Sn^{2+}/Sn}=-0.14V$

Reduction half reaction: $H_2+2e^-\rightarrow H_2(g);E^o_{2H^{+}/H_2}=0.0V$

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the $E^o_{cell}$ of the reaction, we use the equation:

$E^o_{cell}=E^o_{cathode}-E^o_{anode}$

Putting values in above equation, we get:

$E^o_{cell}=0.0-(-0.14)=0.14V$

To calculate the EMF of the cell, we use the Nernst equation, which is:

$E_{cell}=E^o_{cell}-\frac{0.059}{n}\log \frac{[Sn^{2+}]\times p_{H_2}}{[H^+]^2}$

where,

$E_{cell}$ = electrode potential of the cell = ?

$E^o_{cell}$ = standard electrode potential of the cell = +0.14 V

n = number of electrons exchanged = 2

$[H^{+}]=1.39M$

$[Sn^{2+}]=9.35\times 10^{-4}M$

$p_{H_2}=6.56\times 10^{-2}atm$

Putting values in above equation, we get:

$E_{cell}=0.14-\frac{0.059}{2}\times \log(\frac{(9.35\times 10^{-4})\times (6.56\times 10^{-2})}{(1.39)^2})\\\\E_{cell}=0.273V$

Hence, the cell potential of the given electrochemical cell is 0.273 V

4 0

3 years ago

_____ energy is energy available to do work.

Arisa [49]

The answer is C. Free Energy.

Activation energy is the energy that must be exceeded before a chemical reaction can occur. Free energy best describes as energy available to do work.

7 0

3 years ago

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If the percent (mass/mass) for a solute is 8% and the mass of the solution is 200 g, what is the mass of solute in solution?

tatyana61 [14]

Answer:

The answer to your question is 16 g

Explanation:

Data

Percent by mass = 8%

Mass of the solution = 200 g

Mass of solute = ?

Formula

Percent by mass = mass of solute / mass of solution x 100

- Solve for mass of solute

Mass of solute = Percent by mass x mass of solution / 100

- Substitution

Mass of solute = 8 x 200 / 100

- Simplification

Mass of solute = 1600 / 100

- Result

Mass of solute = 16 g

3 0

3 years ago

Read 2 more answers