What is a property of bases?

Chemistry

1 answer:

ycow [4]3 years ago

8 0

Answer:

Explanation:

the answer is slippery touch

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Which of the following statements about the procedure for distillation is false?

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Answer: B) You are to continue heating the round-bottom flask until all liquid has been distilled.

Explanation:

Fractional distillation refers to a method that's useful for the separation of mixtures of solvents whereby there is less than 40°C in the boiling point difference.

With regards to the options given, the incorrect statement about the procedure for distillation is that you are to continue heating the round-bottom flask until all liquid has been distilled. This isn't correct.

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How many grams of KCl can be dissolved in 63.5. g of water at 80°C?

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The barium isotope 133ba has a half-life of 10.5 years. a sample begins with 1.1×1010 133ba atoms. how many are left after (a) 5

Deffense [45]

Given: Half-life of 133Ba = t1/2 = 10.5 years.

The radio-active materials obeys 1st order dissociation kinetics. Therefore we have:
k = 0.693 / t1/2 = 0.693 / 10.5 = 0.066 years-1.

Also, $k = \frac{2.303}{t} log \frac{Co}{Ct}$
where, Co = initial concentration = 1.1×10^10 atoms
Ct = conc. of Ba at time t.
......................................................................................................................

Answer 1: For t = 5 years
 $0.066 = \frac{2.303}{5} log \frac{Co}{Ct}$
Therefore, $log\frac{Co}{Ct}$ = 0.1432
Therefore, Co/Ct = 1.3908
Therefore, Ct = 7.9086 X 10^9 atoms.

Number of 133Ba atoms left after 5 years = 7.9086 X 10^9.
....................................................................................................................

Answer 2: For t = 30 years
$0.066 = \frac{2.303}{30} log \frac{Co}{Ct}$
Therefore, $log\frac{Co}{Ct}$ = 0.8597
Therefore, Co/Ct = 7.2402
Therefore, Ct = 1.5193 X 10^9 atoms.

Number of 133Ba atoms left after 30 years = 1.5193 X 10^9.
........................................................................................................................

Answer 3: t = 180 years
$0.066 = \frac{2.303}{180} log \frac{Co}{Ct}$
Therefore, $log\frac{Co}{Ct}$ = 5.1585
Therefore, Co/Ct = 1.44 X 10^5
Therefore, Ct = 7.6367 X10^4 atoms.

Number of 133Ba atoms left after 180 years = 7.6367 X10^4.

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4 years ago