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Tom [10]
3 years ago
9

It isn't possible to transfer heat from an object at a lower temperature to another object at a _ temperature unless work is don

e
Chemistry
2 answers:
lys-0071 [83]3 years ago
8 0
Heat transfers from high to low. So to complete the statement;

<span>It isn't possible to transfer heat from an object at a lower temperature to another object at a HIGHER temperature unless work is done</span>
lisov135 [29]3 years ago
5 0
Higher. Because this type of heat transfer is conduction, meaning that heat always transfers to cooler objects.
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What mass of water must be added to 5g of nacl to make 5% mass persentage of the solution?
Vitek1552 [10]

Answer:-

95 grams

Explanation:-

Let the mass of water to be added be M

So total mass = 5 + M

So 5% of this solution has 5g of NaCl by mass.

∴ (M+5) x (5/100) = 5

M+5 = 5 x 100/5

M+5=100

M= 100-5

95

So amount of water to be added is 95 gram

8 0
3 years ago
A molecule of glucose is comprised of 6 atoms of carbon, 12 atoms of hydrogen, and 6
Tanya [424]

Answer:

48

Explanation:

because you add 6 and 6 and 12 to get it

7 0
2 years ago
The following data were obtained in a kinetics study of the hypothetical reaction A + B + C → products. [A]0 (M) [B]0 (M) [C]0 (
Vladimir [108]

Answer:

B. First order, Order with respect to C = 1

Explanation:

The given kinetic data is as follows:

A + B + C → Products

     [A]₀     [B]₀    [C]₀       Initial Rate (10⁻³ M/s)

1.   0.4      0.4     0.2       160

2.  0.2      0.4      0.4       80

3.   0.6     0.1       0.2       15

4.   0.2     0.1       0.2        5

5.   0.2     0.2      0.4       20

The rate of the above reaction is given as:

Rate = k[A]^{x}[B]^{y}[C]^{z}

where x, y and z are the order with respect to A, B and C respectively.

k = rate constant

[A], [B], [C] are the concentrations

In the method of initial rates, the given reaction is run multiple times. The order with respect to a particular reactant is deduced by keeping the concentrations of the remaining reactants constant and measuring the rates. The ratio of the rates from the two runs gives the order relative to that reactant.

Order w.r.t A : Use trials 3 and 4

\frac{Rate3}{Rate4}= [\frac{[A(3)]}{[A(4)]}]^{x}

\frac{15}{5}= [\frac{[0.6]}{[0.2]}]^{x}

3 = 3^{x} \\\\x =1

Order w.r.t B : Use trials 2 and 5

\frac{Rate2}{Rate5}= [\frac{[B(2)]}{[B(5)]}]^{y}

\frac{80}{20}= [\frac{[0.4]}{[0.2]}]^{y}

4 = 2^{y} \\\\y =2

Order w.r.t C : Use trials 1 and 2

\frac{Rate1}{Rate2}= [\frac{[A(1)]}{[A(2)]}]^{x}[\frac{[B(1)]}{[B(2)]}]^{y}[\frac{[C(1)]}{[C(2)]}]^{z}

we know that x = 1 and y = 2, substituting the appropriate values in the above equation gives:

\frac{160}{80}= [\frac{[0.4]}{[0.2]}]^{1}[\frac{[0.4]}{[0.4]}]^{2}[\frac{[0.2]}{[0.4]}]^{z}

1 = (0.5)^{z}

z = 1

Therefore, order w.r.t C = 1

8 0
4 years ago
During the apollo missions,an astronaut took a golf ball to the moon. He placed it on the moon’s surface and hit the ball with a
aleksandr82 [10.1K]

Answer:

b.)

Explanation:

Because you would have a different weight on the moon because of it's low gravity

3 0
3 years ago
4NH3 + 5O2-&gt; 4NO + 6H2O<br><br> How many molesof NO are formed if 824g of NH3 react ?
ZanzabumX [31]
824 g NH3 (1 mol/17 g NH3) (4 mol NO/4mol NH3)

48.47 moles NO
4 0
3 years ago
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