Answer:
0.035 N
Explanation:
Parameters given:
Charge q1 = -3.31x10^(-7) C
Charge q2 = -5.7x10^(-7) C.
Distance between them, R = 22 cm = 0.22 m
Electrostatic force between to particles is given as:
F = (k* q1 * q2) / R²
F = (9 * 10^9 * -3.31 * 10^(-7) * -5.7 * 10^(-7)) / 0.22²
F = 0.035 N
Answer:
2513.6 W
Explanation:
Acoustic power = sound intensity × area of hemisphere
Sound intensity = 1 W/m^2
Area of hemisphere = 2πr^2 = 2×3.142×20^2 = 2513.6 m^2
Acoustic power = 1 W/m^2 × 2513.6 m^2 = 2513.6 W
Answer:
The speed is 1.52 m.
Explanation:
Given that,
Displacement =0.270 m
Distance = 0.130 m
Suppose a 0.321-kg mass is attached to a spring with a force constant of 13.3 N/m.
We need to calculate the angular velocity
Using formula of angular velocity
Put the value into the formula
We need to calculate the velocity
Using formula of velocity
Put the value into the formula
Hence, The speed is 1.52 m.
Answer:
- 0.5 m/s²
Explanation:
m = mass of the clarinet case = 3.230 kg
W = weight of the clarinet case in downward direction
a = vertical acceleration of the case
Weight of the clarinet case is given as
W = mg
W = 3.230 x 9.8
W = 31.654 N
F = Upward force applied = 30.10 N
Force equation for the motion of the case is given as
F - W = ma
30.10 - 31.654 = 3.230 a
a = - 0.5 m/s²
