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Virty [35]
3 years ago
5

A baseball hits a car, breaking its window and triggering its alarm which sounds at a frequency of 1210 Hz. What frequency (in H

z) is heard by a boy on a bicycle riding away from the car at 8.25 m/s? Take the speed of sound to be 343 m/s.
Physics
1 answer:
IRINA_888 [86]3 years ago
8 0

Answer:

The frequency of sound heard by the boy is 1181 Hz.

Explanation:

Given that,

Frequency of sound from alarm  f_{0} = 1210\ Hz

Speed = -8.25 m/s

Negative sign show the boy riding away from the car

Speed of sound = 343

We need to calculate the heard frequency

Using formula of frequency

f = f_{0}(\dfrac{v+v_{0}}{v-v_{s}})

Where, f_{0} = frequency of source

v_{0} = speed of observer

v_{s} = speed of source

v = speed of sound

Put the value into the formula

f=1210\times\dfrac{343+(-8.25)}{343-0}

here, source is at rest

f=1180.8\ Hz

f=1181\ Hz

Hence, The frequency of sound heard by the boy is 1181 Hz.

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two tugboats pull a disabled supertanker. each tug exerts a constant force of 2.20×106 n , one at an angle 19.0 ∘ west of north,
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Andrea was watching her brother in the ocean and noticed that the waves were coming into the beach at a frequency of 0.777778 Hz
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3 years ago
NEED HELP !!!!!
goblinko [34]

Answers with Explanations:

1. Answer: True

Explanation:

Muscle cramps happen especially during an <em>"intense workout."</em> The frequency of cramps is related to heat, thus it is important to<u> stay hydrated</u> all throughout the workout. Eating should be done<em> at least 2 to 3 hours</em> <em>prior to workout</em> because eating immediately before exercise leads to undigested food. Such kind of food causes cramps.

2. Answer: True

Explanation: Applying direct pressure immediately after the injury can help <em>decrease bleeding.</em> Blood loss results to <u>blood that is collected under the skin. </u>This turns into the color of blue or black, also known as "bruise." Decrease bleeding would then mean decrease bruising.

Applying pressure also <em>decreases swelling </em>because it restricts the blood flow and fluid from reaching into the injury.

3. Answer: False

Explanation: "Lordosis" refers to the body's<em> natural lordotic curve</em>. This is considered "normal." The excessive inward curve of the lumbar spine is called "hyperlordosis." This is commonly caused by<u> poor posture, lack of exercise, obesity and spinal conditions.</u>

4. Answer: False

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5. Answer: True

Explanation: Keeping the proper posture during exercise <u><em>prevents the body from encountering injuries</em></u>. It also ensures that the body is executing the exercise by<u> using the muscles properly.</u>

6. Answer: False

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7. Answer: False

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9. Answer: True

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10. Answer: True

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11. Answer: all of the above

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12. Answer: True

Explanation: Stretching is appropriately done at the<u> end of a warm-up</u> when the temperature has increased because at this time, the muscles are already flexible. It allows the muscles to be loosened and also aids in better performance during workouts or exercises.

13. Answer: False

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14. Answer: True

Explanation: "Warming-up" is an essential preparation before any workout because it prepares the body by<em> increasing temperature</em> and <em>blood flow to the muscles</em>. Without it, the muscles will become sore and the chance for injuries increases.

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4 0
3 years ago
A student wishes to determine the heat capacity of a coffee-cup calorimeter. After she mixes 108.7 g of water at 60.2°C with 108
Oduvanchick [21]

Answer : The heat capacity of the calorimeter is, 6.72J/g^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

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where,

c_1 = specific heat of water = 4.184J/g^oC

c_2 = specific heat of calorimeter = ?

m_1 = mass of water = 108.7 g

m_2 = mass of calorimeter = 108.7 g

T_f = final temperature of mixture = 35.0^oC

T_1 = initial temperature of water = 60.2^oC

T_2 = initial temperature of calorimeter = 19.3^oC

Now put all the given values in the above formula, we get

(108.7g)\times (4.184J/g^oC)\times (35.0-60.2)^oC=-(108.7g)\times c_2\times (35.0-19.3)^oC

c_2=6.72J/g^oC

Therefore, the heat capacity of the calorimeter is, 6.72J/g^oC

3 0
2 years ago
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