As the pressure on a sample of gas increases, the volume of the sample _____. decreases stays the same increases

Physics

2 answers:

TEA [102]3 years ago

5 0

Answer : As the pressure on a sample of gas increases, the volume of the sample decreases.

Explanation :

According to the Boyle's, law, the pressure of the gas is inversely proportional to the volume of gas at constant temperature and moles of gas.

$P\propto \frac{1}{V}$ (At constant temperature and moles of gas)

From the we conclude that the higher the pressure of gas, lower will be the volume and lower the pressure of gas, higher will be the volume of gas.

Hence, as the pressure on a sample of gas increases, the volume of the sample decreases.

Allisa [31]3 years ago

3 0

By Boyle's law the volume of the sample decreases, provided temperature is constant.

You might be interested in

At some instant and location, the electric field associated with an electromagnetic wave in vacuum has the strength 71.9 V/m. Fi

kirza4 [7]

Answer:

a) Magnetic field strength, B = 2.397 * 10⁻⁷ T

b) Total energy density, U = 4.58 * 10⁻⁸ J/m³

c) Power flow per unit area, S = 13.71 W/m²

Explanation:

a) Electric field strength, E = 71.9 V/m

The relationship between the Electric field strength and the magnetic field strength in vacuum is:

E = Bc where c = 3.0 * 10⁸ m/s

71.9 = B * 3.0 * 10⁸

B = 71.9 / (3.0 * 10⁸)

B = 23.97 * 10⁻⁸

B = 2.397 * 10⁻⁷ T

b) Total Energy Density:

$U = \frac{1}{2} \epsilon_0E^2 + \frac{1}{2} \frac{B^2}{\mu_0} \\U = \frac{1}{2}* 8.85 * 10^{-12}*71.9^2 + \frac{1}{2} \frac{(2.397*10^{-7})^2}{4\pi*10^{-7}}\\U = 2.29 * 10^{-8} + 2.29 * 10^{-8}\\U = 4.58 * 10^{-8} J/m^3$

c)Power flow per unit area

$S = \frac{1}{\mu_0} EB\\S = \frac{1}{4\pi * 10^{-7} } * 71.9 * 2.397 * 10^{-7}\\S = 13.71 W/m^2$

6 0

3 years ago

Which of the following describes a condition in which an individual would not hear an echo?

IrinaVladis [17]

If the echo (the reflected sound) reaches your ear less than about
0.1 second after the original sound, your brain doesn't separate them,
and you're not aware of the echo even though it's there.

If the echo comes from, say, a wall, 0.1 second means you'd have to be
about 17 meters away from the wall. If you're closer than that, then the
echo reaches you in less than 0.1 second and you're not aware of it.

A. 30 meters . . .
   No. You hear that echo easily

B. you're standing within range of both sounds . . .
   No. You hear that echo easily, if you're at least 17 meters from the wall.

C. less than 0.1 second later . . .
   That's it. The echo is there but your brain doesn't know it.

D. 21.5 meters
   No. You hear that echo easily.

4 0

3 years ago

Read 2 more answers

A trombone plays a C3 note. If the speed of sound in air is 343 m/s and the wavelength of this note is

Umnica [9.8K]

The frequency of note C3 is 131 $s^{-1}$ .

<u>Explanation:</u>

Frequency is the measure of repetition of same thing a certain number of times. So frequency is inversely proportional to the wavelength. As wavelength is distance between two successive crests or troughs in a sound wave.

And frequency is the completion of number of cycles in a given time in sound waves. The frequency and wavelength are inversely proportional to each other with velocity of sound being the proportionality constant.

Thus, here the speed of sound is given as 343 m/s, the wavelength of the note is also given as 2.62 m, then frequency will be as follows:

$Frequency=\frac{speed of sound}{Wavelength of note}$