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3 years ago

Could Mars be a suitable alternative to Earth as a second home for humans? Explain your answer.

Physics

1 answer:

SOVA2 [1]3 years ago

8 0

Answer:

yes

Explanation:

After the Earth, Mars is the most habitable planet in our solar system due to several reasons: Its soil contains water to extract. It isn't too cold or too hot. ... Gravity on Mars is 38% that of our Earth's, which is believed by many to be sufficient for the human body to adapt to.

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If the moon disappeared what effect would this have on the earths tides

iogann1982 [59]

The moon has a huge impact on the tides. With the Moon gone, the oceans would become much calmer. The Sun still has its effect on them known as the solar tides. Surfers wouldn't be completely devoid of waves.

4 0

3 years ago

Read 2 more answers

A student has a displacement of 304 m north in 180 s. What was the student's average velocity?

DanielleElmas [232]

Answer:

v = 1.69 m/s

Explanation:

Given that,

Displacement of the student is 304 m due North and it takes 180 s.

We need to find the student's average velocity. Using formula of velocity.

Velocity = displacement/time

$v=\dfrac{304\ m}{180\ s}\\\\v=1.69\ m/s$

Hence, the student's average velocity is 1.69 m/s.

6 0

4 years ago

First law of equilibrium

valentina_108 [34]

Answer:

For an object to be an equilibrium it must be experiencing no acceleration.

Explanation:

Hope it helps.

5 0

3 years ago

Coulomb's law for the magnitude of the force FFF between two particles with charges QQQ and Q′Q′Q^\prime separated by a distance

SSSSS [86.1K]

Answer:

${F_{tot} = -1.092*10^{-2}N$

Explanation:

The question: What is the net force exerted by these two charges on a third charge q_3 = 47.0 nC placed between q_1 and q_2 at x_3 = -1.240 mm ?

<u>Your answer may be positive or negative, depending on the direction of the force.</u>

Solution:

The coulomb force is given by the equation

$F =k\dfrac{q_1 q_2}{d^2}.$

where $d$ is the separation between the charges $q_1$ and $q_2$ .

Now, in our case

$q_1=-13.5nC=-13.5*10^{-9}C$

$q_2=-1.735nC=-1.735*10^{-9}C$

$q_3= 47*10^{-9}C$

The separation between charges $q_3$ and $q_1$ is

$d_{31}= (-1.240mm)-(-1.735mm)=0.495mm=4.95*10^{-4} m$

Therefore, the force between them is

$F_{31} = (9*10^9NmC^{-2})\dfrac{47*10^{-9}*(-13.5*10^{-9})}{4.95*10^{-4}} =-0.01152N$

and it is directed in the negative x-direction.

The separation between charges $q_2$ and $q_3$ is

$d_{23} =-1.240mm-0=-1.240*10^{-3}m$

therefore, the force between them is

$F_{23} =(9*10^9Nm^2C^{-2})\dfrac{47*10^{-9}C*(-1.735*10^{-9}C)}{-1.240*10^{-3}m}=5.94*10^{-4}N$

Therefore the total force on charge $q_3$ is

$F_{tot} =5.94*10^{-4}-0.01152N = -0.010926N\\\\\boxed{F_{tot} = -1.092*10^{-2}N}$

8 0

3 years ago

This is a type of friction experienced within liquids and gases. It depends on:__________.

Aleksandr-060686 [28]

Answer:

(1) how thick the fluid is <u>viscosity</u>

Explanation:

This is a type of friction experienced within liquids and gases. It depends on:__________.

(1) how thick the fluid is_______?

(2) how the shape of the object?

(3) how the speed of the object?

the thickness of a fluid is known as viscosity. the more viscous a fluid is the more frictional force is exerted on an object by the fluid

frictional force is an opposing force that resist the movement of two surfaces in contact, there are to types 0f frictional force

1. static frictional force

2. dynamic frictional force

4 0

3 years ago