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3 years ago

Why would a flat sheet of paper and a wad of paper with the same mass not fall through the air at the same rate?

Physics

2 answers:

Gelneren [198K]3 years ago

7 0

The flat sheet of paper has more surface area than the crumpled ball

tatyana61 [14]3 years ago

7 0

The flat sheet has a larger surface area, so there will be more air resistance upon it. You have two forces on your paper, gravity (down) and normal (up.) Although gravity is stronger than the normal of air, the difference between the down force and the up is smaller. For example:

If gravity is 10 newtons and the air resistance is 5, then the force is:
10N-5N= 5N

If gravity is in a vacuum, then air resistance is 0:
10N-0N= 10N

In the first example, you get half as much force bringing your paper down, so it will fall at a slower rate.

When the paper is crumpled, the air resistance is lower because their is less surface area for the normal to work on.

If gravity is 10 newtons and the air resistance is 2, then the force is:
10N-2N= 8N

More force, falling faster.

Ignore this if you don't want to be confused:
Technically, they do fall at the same rate, because all objects fall at the same speed regardless of mass. The illusion of time difference comes from friction.

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On January 22, 1943, the temperature in Spearfish, South Dakota, rose from -4.0∘F∘F to 45.0∘F∘F in just 2 minutes. What was the

Margaret [11]

Answer:

The change in temperature, $\Delta T=9.45^{\circ} C$

Explanation:

Given that,

The temperature in Spearfish, South Dakota, rose from $-4^{\circ} F\ to\ 45^{\circ} F$ in just 2 minutes. We need to find the temperature change in Celsius degrees. Change in temperature is given by final temperature minus initial temperature such that,

$\Delta T=T_f-T_i\\\\\Delta T=45-(-4)\\\\\Delta T=49^{\circ}F$

The relation between degrees Celsius and degrees Fahrenheit is given by :

$F=1.8C+32$

Here, F = 49 degrees

$49=1.8C+32\\\\\Delta T=9.45^{\circ} C$

So, the change in temperature is 9.45 degree Celsius. Hence, this is the required solution.

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2 years ago

an airplane traveling 245 m/s east expericences turbulence, so the pilot slows down to 230 m/s. it takes the pilot 7 seconds to

lana66690 [7]

Answer:

a=v-u/t

a=245-230/7

a=2

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2 years ago

When an object is raised vertically, work is done against __________. What one word completes the sentence?

Rasek [7]

Gravity Gravitational Force of Gravity

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2 years ago

In a circus act, a 70 kg clown is shot from a cannon with an initial velocity of 17 m/s at some unknown angle above the horizont

EleoNora [17]

Answer:

$K_{2}=7302.4J$

Explanation:

Given the initial velocity of the clown, his mass and final height we can calculate the final kinetic energy using the <em><u>conservation of total mechanical energy</u></em>

$K_{1}+U_{1}=K_{2}+U_{2}$

$K_{2}=K_{1}+U_{1}-U_{2}$

$K_{2}=\frac{1}{2}mv_{1}^{2}+mgh_{1}-mgh_{2}$

Since $h_{1}=0$

$K_{2}=\frac{1}{2}mv_{1}^{2}-mgh_{2}$

$K_{2}=\frac{1}{2}(70kg)(17m/s)^2-(70kg)(9.8m/s^2)(4.1m)=7302.4J$

$K_{2}=7302.4J$

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2 years ago

The distance from the Earth to the Sun is known as an astronomical unit (AU). This distance is also equal to 1.496e+011 m. Neptu

Lerok [7]

Answer:

The distance from the Sun to Neptune is 29,41 AU.

Explanation:

We know, from the sentence, that the orbit of Neptune has an average diameter around 8.80*10⁹km.

Now, we can calculate the radius of this orbit, which is equivalent to the distance from thsi planet to the Sun. Let's recall tha the radius is the half of the diameter.

$R=\frac{8.80\cdot 10^{9}}{2}=4.4\cdot 10^{9}km=4.4\cdot 10^{12}m$

Ok, we know that 1.496*10¹¹m is an AU, therefore we have:

$4.4\cdot 10^{12}m\cdot \frac{1 AU}{1.496\cdot 10^{11}}=29,41 AU$

Finally, the distance R is 29,41 AU.

I hope it helps you! :)

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2 years ago