You did not include the list but F is fluorine. The first halogen.
So, you can expect that the other members of the same group (halogens, column 17 of the periodic table) exhibit similar chemical behavior (reactivity).
So, I am sure your list contains one or more of theses elements: Cl (chlorine), Br (bromine), and I (iodine).
All of them you can expect to also be reactive non metal.
Answer:
Option a,
Explanation:
According to Arrhenius concept of acids and bases, acids are those substances which releases H+ in aqueous solution and bases are those which releases OH- in aqueous solution.
Among the given only can release in aqueous solution.
LiOH releases , therefore it is an Arrhenius base.
and cannot releases .
So, the correct option is option a.
Answer:
ClAl
Explanation:
* = electron
Cl (17) * * * * * * *
Al (13) * * *
If one of aluminum's electrons were added to chlorine to make a full shell, still have 2 left over. So you need another:
Cl * * * * * * * * (full)
Cl * * * * * * *
Al * *
Still have another left over. Aluminum needs to lose another one of its valence electrons to be able to have a full shell. So you take another chlorine:
Cl * * * * * * * * (full)
Cl * * * * * * * * (full)
Cl * * * * * * *
Al *
You will eventuate with 3Cl and 1Al, or ClAl. Modeled above:
Answer:
C because both are way too big to pass through the filter
Explanation: