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steposvetlana [31]
3 years ago
5

In a double-replacement reaction, the___. Fast Help!

Chemistry
1 answer:
Anarel [89]3 years ago
5 0

Answer:

reactants are two ionic compounds. Explanation: A double-replacement reaction is different from a single-replacement reaction because a double-replacement reaction is a reaction between two ionic compounds while in a single-replacement reaction one atom replace another atom.

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Sort the compounds: conjugated or non conjugated. -but-2-enoic acid -butanoic acid -hex-4-en-3-one -hexan-3-one
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A certain substance X condenses at a temperature of 123.3 degree C . But if a 650. g sample of X is prepared with 24.6 g of urea
Pavel [41]

Answer:

<u>The molal boiling point elevation constant is 1.59 ≈  1.6</u> Kkgmol^{-1}

Explanation:

To solve this question , we will make use of the equation ,

ΔT_{b} = i*K_{b} *m

<em>where , </em>

  • <em>ΔT_{b} is the change in boiling point of the substance X ( °C or K)</em>
  • <em>i is the Vant Hoff Factor which = 1 in this case ( no unit )</em>
  • <em>K_{b} is the mola boiling point elevation constant of X ( Kkgmol^{-1})</em>
  • <em>m is the molality of the solution which has (NH_{2})_{2} CO as the solute and  X as the solution (molkg^{-1})</em>

  1. ΔT_{b} = 124.3 -123.3 = 1 °C or K;
  2. i=1;
  3. m= \frac{moles of solute}{weight of solvent(kg)}molkg^{-1}

           ∴ m = \frac{\frac{24.6}{60} }{\frac{650}{1000} }

  • <em>as the weight of (NH_{2})_{2} CO is 60g and thus number of moles = \frac{24.6}{60}</em>
  • <em>and the weight of solvent in kg is \frac{650}{1000}</em>

    4. K_{b} ⇒ ?

∴

1=1*K_{b} *\frac{\frac{24.6}{60} }{\frac{650}{1000} }

⇒ K_{b} = 1.59 ≈ 1.6 Kkgmol^{-1}

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