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Pavel [41]
3 years ago
7

How to round numbers and find significant digits in physics?? Simple answer? Please???

Physics
1 answer:
Mrrafil [7]3 years ago
3 0

Answer:

Heya how have you been doing

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Help me with # 3 & #4 please
defon

Answer:

DveC başarılar yardı olduysam sevinirim

6 0
3 years ago
3) If an airplane is in flight cruising at constant velocity, what can be said about the net work
Crazy boy [7]

Explanation:

<h2>Yes!</h2>

<h3>In physics, constant velocity occurs when there is no net force acting on the object causing it to accelerate. In terms of airplane flight, the two main forces influencing its velocity forward are drag and thrust. At a constant altitude, when the force of thrust equals the opposing force of drag, then the airplane will experience uniform motion in one direction. This can be further explained by Newton’s First Law. </h3>
6 0
3 years ago
How does atomic bombs work?​
yarga [219]

Answer:

Nuclear fission produces the atomic bomb, a weapon of mass destruction that uses power released by the splitting of atomic nuclei. When a single free neutron strikes the nucleus of an atom of radioactive material like uranium or plutonium, it knocks two or three more neutrons free.

Explanation:

this chain reaction releases tremendous amount of energy

8 0
3 years ago
Read 2 more answers
A particle moving along the x-axis has its velocity described by the function vx =2t2m/s, where t is in s. its initial position
Nesterboy [21]

The position of the object at time t =2.0 s is <u>6.4 m.</u>

Velocity vₓ of a body is the rate at which the position x of the object changes with time.

Therefore,

v_x= \frac{dx}{dt}

Write an equation for x.

dx=v_xdt\\ x=\int v_xdt

Substitute the equation for vₓ =2t² in the integral.

x=\int v_xdt\\ =\int2t^2dt\\ =\frac{2t^3}{3} +C

Here, the constant of integration is C and it is determined by applying initial conditions.

When t =0, x = 1. 1m

x= \frac{2t^3}{3} +C\\ x_0=1.1\\ x= (\frac{2t^3}{3} +1.1)m

Substitute 2.0s for t.

x= (\frac{2t^3}{3} +1.1)m\\ =\frac{2(2.0)^3}{3} +1.1\\ =6.43 m

The position of the particle at t =2.0 s is <u>6.4m</u>




5 0
3 years ago
In the problem below, what is the student showing?
Phantasy [73]

Answer:

S<em>tudent showing the volume of cube</em>

                      V = a³

                       if a = 3 cm

  Then volume is a³ = 3 ×3 × 3

                                 = 27 cm³

6 0
3 years ago
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