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pishuonlain [190]
3 years ago
10

an ideal gas is confined to a container with adjustable volume. the number of moles, n, and temperature, t, are constant. by wha

t factor will the volume change if pressure increase by a factor of 5.1
Physics
1 answer:
Katyanochek1 [597]3 years ago
6 0

Answer:

The volume will decrease by a factor of 10/51.

Explanation:

Hello,

In this case, since both moles and temperature remain constant, we can use the Boyle's law that relates the volume and pressure as an inversely proportional relationship:

P_1V_1=P_2V_2

Thus, since the pressure increases by a factor of 5.1 (statement), we have:

P_2=5.1P_1

Thus, the final volume is:

V_2=\frac{P_1V_1}{P_2} =\frac{P_1V_1}{5.1P_1}\\\\V_2=\frac{10}{51}V_1

It means that the volume will decrease by a factor of 10/51.

Regards.

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At time t seconds, the mass has angular speed

\omega = \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) t

and hence linear speed

v = (1.4\,\mathrm m) \omega = (1.4\,\mathrm m) \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) t

After 8 s, its linear speed is

v = (1.4\,\mathrm m) \left(3.31\dfrac{\rm rad}{\mathrm s^2}\right) (8\,\mathrm s) = 37.072 \dfrac{\rm m}{\rm s} \approx 37 \dfrac{\rm m}{\rm s}

and has centripetal acceleration with magnitude

a = \dfrac{v^2}{1.4\,\rm m} \approx 981.667\dfrac{\rm m}{\mathrm s^2} \approx 980 \dfrac{\rm m}{\mathrm s^2}

To maintain this linear speed, by Newton's second law the required centripetal force should have magnitude

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5 0
2 years ago
The mass of the earth is 5.96/10kg^24. The radius of the earth is approximately 6.37x10^6 calculate the force of gravity
n200080 [17]
<h2>Answer:g=9.79ms^{-2},A object of mass m at the surface of earth experiences a force mg</h2>

Explanation:

Let M be the mass of earth.

Let R be the radius of earth.

Let G be the universal gravitational constant.

Given,

M=5.96\times 10^{24}Kg

R=6.37\times 10^{6}m

G=6.67259 \times 10^{-11}Nm^{2}Kg^{-2}

Let g be the acceleration due to gravity.

Then,g=\dfrac{GM}{R^{2}}

g=\frac{6.67259 \times 10^{-11}\times 5.96\times 10^{24}}{(6.37\times 10^{6})^{2}}

g=9.79ms^{-2}

A object of mass m at the surface of earth experiences a force mg

3 0
3 years ago
How does the law of conservation apply to Earth's Energy Budget?
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The balance between incoming energy from the sun and outgoing energy from Earth ultimately drives our climate. This energy balance is governed by the first law of thermodynamics, also known as the law of conservation of energy.

4 0
2 years ago
. A 40.0-kg child standing on a frozen pond throws a 0.500-kg stone to the east with a speed of 5.00 m/s. Neglecting friction be
tamaranim1 [39]

Answer:

Explanation:

A 40kg child throw stone of 0.5kg

At a direction of 5m/s

Recoil can be calculated using recoil of a gun formula

m_1•v_1 + m_2•v_2

m_1•v_1 = -m_2•v_2

The negative sign show that the momentum of the boy is directed oppositely to that of the stone

m_1 Is mass of boy

v_1 is the recoil velocity of the boy

m_2 is mass of stone

v_2 is the velocity of stone

Then,

m_1•v_1 = -m_2•v_2

40•v_1 = -0.5 × 5

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6 0
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konstantin123 [22]

the electric force decreases because the distance has an indirect relationship to the force

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where

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r is the distance between the two objects

As we can see from the formula, the magnitude of the force is inversely proportional to the square of the distance: so, when the distance between the object increases, the magnitude of the force decreases.

3 0
3 years ago
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