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Nuetrik [128]
3 years ago
9

Types of cell combination? in electricity​

Physics
1 answer:
Grace [21]3 years ago
7 0

Answer:

Series and Parallel

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Due to attraction ... of opposite charges
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I need help with some graph.<br><br> Which graph shows acceleration?
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The first graph

Explanation:

Graph A shows acceleration.

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Sugar molecules can be oxidized in the cell of animals . This oxidation releases energy for the animal to use. From what soured
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A physics professor wants to perform a lecture demonstration of Young's double-slit experiment for her class using the 633-nm li
Alexeev081 [22]

Note: if the professor wants the distance between the m = 0 and m = 1 maxima to be 25 cm

Answer:

d = 1.0128×10⁻⁵m

Explanation:

given:

length L = 4.0m

maximum distance between m = 0 and m = 1 , y = 25cm = 0.25m

wavelength λ = 633nm = 633×10⁻⁹m

note:

dsinθ = mλ (constructive interference)

where d is slit seperation, θ is angle of seperation , m is order of interference , and λ is wavelength

for small angle

sinθ ≈ tanθ

d (\frac{y}{L})  = mλ

d (\frac{y}{L}) = (1)(633nm)

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d = 1.0128×10⁻⁵m

6 0
2 years ago
A catapult with a spring constant of 10,000 N/m is used to launch a target from the deck of a ship. The spring is compressed a d
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Answer:

(C) 40m/s

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Given;

spring constant of the catapult, k = 10,000 N/m

compression of the spring, x = 0.5 m

mass of the launched object, m = 1.56 kg

Apply the principle of conservation of energy;

Elastic potential energy of the catapult = kinetic energy of the target launched.

¹/₂kx² = ¹/₂mv²

where;

v is the target's  velocity as it leaves the catapult

kx² = mv²

v² = kx² / m

v² = (10000 x 0.5²) / (1.56)

v² = 1602.56

v = √1602.56

v = 40.03 m/s

v ≅ 40 m/s

Therefore, the target's velocity as it leaves the spring is 40 m/s

6 0
2 years ago
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