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mojhsa [17]
2 years ago
6

What is the morality of a solution witch composed of 200.12 g HCI in 5.2 L solution?

Chemistry
1 answer:
Dovator [93]2 years ago
5 0

Answer:

1.06 M

Explanation:

200.12/36.46= ans./5.2

grams/atomic mass = ans./volume (L)

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I WILL DIE I HAVE A KNIFE IN MY HAND. ANSWER WITH EXPLANATION. If the sound is high pitched, then the wave's frequency would hav
enyata [817]

Answer:

Option A - High frequency, short wavelength.

Explanation:

<em>If the sound is high then the frequency is also high but short-wavelength means lots of waves that always have a high pitch-sound and a high frequency. </em>

3 0
3 years ago
The correct name for HIO2?
valentinak56 [21]

Answer:

iodous acid

Explanation:

iodous acid would also be known as HIO2

6 0
3 years ago
How many grams of sodium chloride are present in a 0.75 M solution with a volume of 500.0 milliliters?
LUCKY_DIMON [66]
The units for molarity is moles of solute per liter of solution which means if you multiply the molarity of a solution by its volume you get how many moles of solute are in the solution. (0.75Mx0.5L=0.375mol NaCl) Then you can multiply the moles of sodium chloride (0.375 mol) by its molar mass (58.45 g/mol) to get 21.92g of sodium chloride. That means there is 21.92 grams of sodium chloride in 500mL of 0.75M solution. I hope this helps. Let me know if anything is unclear.
6 0
3 years ago
A tablet of Pain Be Gone Aspirin, which had a mass of 1.213 g, was pulverized and 1.159 g were dissolved in 10.0 mL of ethyl alc
Elan Coil [88]

Answer:

a. Moles of NaOH  = 0.001643 moles

b. 0.296 g

c. 0.3098 g

d. Not acceptable

Explanation:

a.

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For NaOH :

Molarity = 0.1052 M

Volume = 15.62 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 15.62×10⁻³ L

Thus, moles of NaOH :

Moles=0.1052 \times {15.62\times 10^{-3}}\ moles

Moles of NaOH  = 0.001643 moles

b.

The reaction of NaOH with the acetylsalicylic acid is in the ratio of 1:1.

Thus, Moles of NaOH = Moles of acetylsalicylic acid = 0.001643 moles

Molar mass of acetylsalicylic acid = 180.16 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

Mass = Moles * Molar mass = 0.001643 moles * 180.16 g/mol = 0.296 g

c.

1.159 g of sample contains 0.296 g of acetylsalicylic acid

1.213 g of sample contains \frac{0.296}{1.159}\times 1.213 g of acetylsalicylic acid

Mass of acetylsalicylic acid = 0.3098 g = 309.8 mg

d. Sample contains = 309.8 mg

Manufacturer claiming = 315 mg to 335 mg

Thus , it is not acceptable.

5 0
3 years ago
A sample of Ca(OH)2 is considered to be an Arrhenius base because it dissolves in water to yield
postnew [5]
The answer is C. Arrhenius bases increase the concentration of OH- in solution.
8 0
3 years ago
Read 2 more answers
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