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lana [24]
3 years ago
13

Which of the following has the greatest kinetic energy? A. a mass of 4m at velocity v. B. a mass of 3m at velocity 2v. C. a mass

of 2m at velocity 3v. D. a mass of m with a velocity of 4v.
Physics
1 answer:
Artist 52 [7]3 years ago
4 0

Answer:

Option C

Explanation:

Kinetic energy is the energy that the body possesses by virtue of its motion.

The formula for Kinetic energy is given by \frac{1}{2} mv^2

Using this formula let us find kinetic energy for the bodies given and find out which is the greatest

A) KE = \frac{1}{2} (4m)(v^2) = 2mv^2

B) KE =\frac{1}{2} (3m)(2v)^2 = 6mv^2

C) KE = \frac{1}{2} (2m)(3v)^2 = 9mv^2

D) KE = \frac{1}{2} (3)(4v)^2 = 8mv^2

Comparing these we find that 9mv^2 is the highest.

Hence option C is the answer.

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In which situation does heating a substance generally change the temperature?
marta [7]
The correct answer is C
5 0
3 years ago
Review. From a large distance away, a particle of mass 2.00 g and charge 15.0σC is fired at 21.0 i^ m/s straight toward a second
MissTica

(a)

Determine the system's initial configuration at ri = infinite particle separation and the system's final configuration at the point of closest approach.

Since the two-particle system is not being affected by any outside forces, we may treat it as an isolated system for momentum and use the momentum conservation law.

m1v1 + m1v2 = (m1+m2)v

The second particle's starting velocity is zero, so:

m1v1  = (m1+m2)v

After substituting the values we get,

v = 6i m/s

(b)

Since the two particle system is also energy-isolated, we may use the energy-conservation principle.

dK + dU = 0

Ki +Ui = Kf + Uf

Substituting the values,

1/2m1v1^2i + 1/2 m2v2^2i + 0 = 1/2m1v1^2f + 1/2m2v2^2f +ke q1q2/rf

The second particle's initial speed is 0 (v2 = 0). Additionally, both the first and second particle's final velocity have the same value, v. Put these values in place of the preceding expression:

1/2m1v1^2i  = 1/2m1v1^2 + 1/2m2v2^2 +ke q1q2/rf

After solving we get,

rf = 2ke q1q2 / m1v1^2 - (m1+m2)v^2

Substituting the values we get,

rf = 3.64m

(c)

v1f = (m1-m2 / m1 + m2) v1i

v1f  = -9i m/s

(d)

v2f =  (2m1/ m1 +m2) v1i

After substituting the values,

v2f = 12i m/ s

Question :

Review. From a large distance away, a particle of mass 2.00 g and charge 15.0 \muμC is fired at 21.0 m/s straight toward a second particle, originally stationary but free to move, with mass 5.00 g and charge 8.50 \muμC. Both particles are constrained to move only along the x axis. (a) At the instant of closest approach, both particles will be moving at the same velocity. Find this velocity. (b) Find the distance of closest approach. After the interaction, the particles will move far apart again. At this time, find the velocity of (c) the 2.00-g particle and (d) the 5.00-g particle. \hat{i}

To learn more about  momentum conservation law click on the link below:

brainly.com/question/7538238

#SPJ4

5 0
2 years ago
A tall, open container is full of glycerine. At what depth h below the surface of the glycerine is the pressure 2370 Pa greater
Mice21 [21]

Answer:

So, at the depth of 24 cm below the surface of the glycerine the pressure is  2970 Pa. Hence, this is the required solution.

Explanation:

Given that,

Pressure exerted by the surface of glycerine, P = 2970 Pa and it is greater than atmospheric pressure.

The density of glycerine,  

We need to find the depth h below the surface of the glycerine. The pressure due to some depth is given by :

h = 0.24 meters

or

h = 24 cm

5 0
3 years ago
A train travels 200km/hr. how much distance will the train be from the station in 2.5 hours?
SCORPION-xisa [38]

Answer:

500km

Explanation:

Given parameters:

Speed  = 200km/hr

Time taken  = 2.5hrs

Unknown:

Distance  = ?

Solution:

To solve this problem, we use the speed, time and distance equation.

   Therefore;

  Distance  = Speed x time

So;

  Distance  = 200 x 2.5  = 500km

6 0
2 years ago
A wave will go faster through a liquid at ____________ temperatures
cupoosta [38]
<h3><u>Answer;</u></h3>

Higher temperatures

A wave will go faster through a liquid at <em><u>highe</u></em><u>r </u>temperatures

<h3><u>Explanation;</u></h3>
  • <em><u>Mechanical waves are types of waves that require a material medium for transmission.</u></em> An example of mechanical wave is the sound wave whose transmission occurs in medium such as solids, liquids and gases.  
  • <em><u>The transmission of mechanical waves involves vibration of particles through the medium of transmission, thus transfer of energy from one point to another. </u></em>The vibration of particle may be in the form of a longitudinal wave or a transverse wave.  
  • <em><u>Increasing the temperature in a medium increases the kinetic energy of the particles in the medium and thus increasing the speed at which the particles vibrates and thus aiding a faster transmission of a wave.</u></em>
7 0
3 years ago
Read 2 more answers
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