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3 years ago

Which is not a compound? oxygen gas water silicon dioxide carbon dioxide gas

Chemistry

1 answer:

olchik [2.2K]3 years ago

7 0

Answer:

Oxygen gas

Explanation:

It is a pure element. The rest are compounds made up of two or more elements. For eg silicon dioxide is made of silicon and oxygen.

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26 POINTS!

lawyer [7]

Answer:I think it’s A.Positive. Not sure though.

Explanation:

7 0

3 years ago

Read 2 more answers

Is this a redox reaction? give evidence (many points plz answer) 2Mg + CO2 → 2MgO + C

Aleonysh [2.5K]

Answer:

$\boxed{yeah}$

Explanation:

$CO_2 \: is \: reduced \: to→C \: by \: 2M_g \: (the \: reducing \: agent): while \\ 2M_g \: is \: oxydized \: to→2M_gO \: by \: CO_2 \: (the \: oxydizing \: agent)$

6 0

2 years ago

The freezing point of ethanol, CH3CH2OH, is -117.300 °C at 1 atmosphere. Kf(ethanol) = 1.99 °C/m

MAXImum [283]

Answer : The molecular weight of this compound is 891.10 g/mol

Explanation : Given,

Mass of compound = 12.70 g

Mass of ethanol = 216.5 g

Formula used :

$\Delta T_f=i\times K_f\times m\\\\T_f^o-T_f=i\times T_f\times\frac{\text{Mass of compound}\times 1000}{\text{Molar mass of compound}\times \text{Mass of ethanol}}$

where,

$\Delta T_f$ = change in freezing point

$T_f^o$ = temperature of pure ethanol = $-117.300^oC$

$T_f$ = temperature of solution = $-117.431^oC$

$K_f$ = freezing point constant of ethanol = $1.99^oC/m$

i = van't hoff factor = 1 (for non-electrolyte)

m = molality

Now put all the given values in this formula, we get

$(-117.300)-(-117.431)=1\times 1.99^oC/m\times \frac{12.70g\times 1000}{\text{Molar mass of compound}\times 216.5g}$

$\text{Molar mass of compound}=891.10g/mol$

Therefore, the molecular weight of this compound is 891.10 g/mol

7 0

2 years ago

I'm currently doing a Castle Learning part teacher and it's graded

kipiarov [429]

See the image below.

An excited electron is in a high-energy state.

When it drops to the lower-level ground state, it must get rid of this excess energy by emitting it as a quantum of light.

4 0

3 years ago

Write a balanced equation for the complete combustion of propane, C3H8 . Do not enter phase symbols. Enter the alkane formula as

Anastaziya [24]

Answer:

C3H8 + 5O2 => 3CO2 + 4H2O

Explanation:

Hydrocarbon combustion is the reaction between a hydrocarbon and O2 producing CO2 and water.

C3H8 + O2 => CO2 + H2O

First we balance the C and H.

C3H8 + O2 => 3CO2 + 4H2O

Now we balance O for the answer!

C3H8 + 5O2 => 3CO2 + 4H2O

3 0

3 years ago