Given the model from the question,
- The products are: N₂, H₂O and H₂
- The reactants are: H₂ and NO
- The limiting reactant is H₂
- The balanced equation is: 3H₂ + 2NO —> N₂ + 2H₂O + H₂
<h3>Balanced equation </h3>
From the model given, we obtained the ffolowing
- Red => Oxygen
- Blue => Nitrogen
- White => Hydrogen
Thus, we can write the balanced equation as follow:
3H₂ + 2NO —> N₂ + 2H₂O + H₂
From the balanced equation above,
- Reactants: H₂ and NO
- Product: N₂, H₂O and H₂
<h3>How to determine the limiting reactant</h3>
3H₂ + 2NO —> N₂ + 2H₂O + H₂
From the balanced equation above,
3 moles of H₂ reacted with 2 moles of NO.
Therefore,
5 moles of H₂ will react with = (5 × 2) / 3 = 3.33 moles of NO
From the calculation made above, we can see that only 3.33 moles of NO out of 4 moles given are required to react completely with 5 moles of H₂.
Thus, H₂ is the limiting reactant
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Answer:
The solute is the substance that is being dissolved,
Explanation:
A solution is a homogeneous mixture consisting of a solute dissolved into a solvent .
Answer:
See the answer and explanation below , please.
Explanation:
A conjugate base is defined as that formed after an acid donates its proton.
For each article, a continuation of the conjugate bases (highlighted in bold), for dissociation in water:
a) HF + H20 --> F- + H30+
b) H20+ H20 --> OH- + H30+
C)H2PO3- + H20--> HPO3 2- + H30+
d) HSO4- + H20 --> SO4 2- + H30+
E) HCL02 + H20 --> CLO02 - + H30+
The missing part of the equation is found to be 4/2He. Option A
<h3>What are nuclear equations?</h3>
The term nuclear equations have to do with the type of equation in which one type of nucleus is transformed into another sometimes by the bombardment or loss of a particle.
Now the full equation ought to be written as 7/3Li + 1/1H -----> 4/2He + 4/2He. This is because the total mass on the left is 8 and the total charge on the left is 4.
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