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klio [65]
3 years ago
12

For each chemical equation below, write the number of product molecules that will form from the reaction.

Chemistry
1 answer:
Gekata [30.6K]3 years ago
4 0

Answer:

a. 5 moles of CO₂

b. 2 moles of NaCl

c. 3 moles of H₂CO₃

Explanation:

1a. Carbon reacts with oxygen to produce carbon dioxide according to equation below:

C + O₂ ----> CO₂

From the equation of reaction, one mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide.

In the given reaction, therefore, 5 moles of carbon will only react with 5 moles of oxygen to produce 5 moles of carbon dioxide. Oxygen is in excess, carbon is the limiting reactant and 5 moles of carbon dioxide are produced. The equation is given below :

5 C + 6 O₂ ---> 5 CO₂

1b. Sodium reacts with chlorine to produce sodium chloride according to the equation below:

2 Na + Cl₂ ---> NaCl

From the equation of reaction, 2 moles of sodium reacts with one mole of chlorine to produce one mole of sodium chloride.

In the given reaction, therefore, 4 moles of sodium will react with only 2 moles of chlorine to produce 2 moles of sodium chloride. Chlorine is in excess, sodium is the limiting reactant and 2 moles of sodium chloride are produced. The equation is given as follows: 4 Na + 8 Cl₂ ---> 2 NaCl

1c. Carbon dioxide reacts with water to produce carbonic acid according to the equation: CO₂ + H₂O ---> H₂CO₃

From the equation of reaction one mole of carbon dioxide reacts with one mole of water to produce one mole of carbonic acid.

In the given reaction, therefore, 3 moles of carbon dioxide will react with only 3 moles of water to produce 3 moles of carbonic acid. Water is in excess, carbon dioxide is the limiting reactant and 3 moles of carbonic acid are produced. The equation is given as follows: 3 CO₂ + 4 H₂O ---> 3 H₂CO₃

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Calculate the millimoles of solute in 1.88 L of a 0.00713 M NaCN solution. millimoles:
konstantin123 [22]

Answer:

13.4 milimoles.

Explanation:

The following data were obtained from the question:

Volume = 1.88 L

Molarity = 0.00713 M

Millimoles of NaCN =?

Next, we shall determine the number of mole NaCN in the solution. This can be obtained as follow:

Molarity = mole /Volume

Volume = 1.88 L

Molarity = 0.00713 M

Mole of NaCN =?

Molarity = mole /Volume

0.00713 = moles of NaCN /1.88

Cross multiply

Mole of NaCN = 0.00713 × 1.88

Mole of NaCN = 0.0134 mole

Finally, we shall convert 0.0134 mole to Millimoles. This can be obtained as follow:

1 mole = 1000 millimoles

Therefore,

0.0134 mole = 0.0134 × 1000

0.0134 mole = 13.4 milimoles

Therefore, the millimoles of the solute, NaCN in the solution is 13.4 milimoles

7 0
4 years ago
What’s plastic.<br> I need this with own words also it has to be half a page
Ket [755]

Answer:

plastic is made up of a wide variety of synthetic materials but use polymers as the main ingredient. Their plasticity makes it easy for plastics to be moulded, extruded or pressed into solid objects of various shapes.

Explanation:

hope this helped :D

3 0
2 years ago
Given the following at 25C calculate delta Hf for HCN (g) at 25C. 2NH3 (g) +3O2 (g) + 2CH4 (g) ---&gt; 2HCN (g) + 6H2O (g) delta
AysviL [449]

<u>Answer:</u> The \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

<u>Explanation:</u>

Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles. The equation used to calculate enthalpy change is of a reaction is:

\Delta H_{rxn}=\sum [n\times \Delta H_f(product)]-\sum [n\times \Delta H_f(reactant)]

For the given chemical reaction:

2NH_3(g)+3O_2(g)+2CH_4(g)\rightarrow 2HCN(g)+6H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H_{rxn}=[(2\times \Delta H_f_{(HCN)})+(6\times \Delta H_f_{(H_2O)})]-[(2\times \Delta H_f_{(NH_3)})+(3\times \Delta H_f_{(O_2)})+(2\times \Delta H_f_{(CH_4)})]

We are given:

\Delta H_f_{(H_2O)}=-241.8kJ/mol\\\Delta H_f_{(NH_3)}=-80.3kJ/mol\\\Delta H_f_{(CH_4)}=-74.6kJ/mol\\\Delta H_f_{(O_2)}=0kJ/mol\\\Delta H_{rxn}=-870.8kJ

Putting values in above equation, we get:

-870.8=[(2\times \Delta H_f_{(HCN)})+(6\times (-241.8))]-[(2\times (-80.3))+(3\times (0))+(2\times (-74.6))]\\\\\Delta H_f_{(HCN)}=135.1kJ

Hence, the \Delta H_f for HCN (g) in the reaction is 135.1 kJ/mol.

8 0
3 years ago
By which process aqua fortis is manufactured
kap26 [50]

Answer: Aqua fortis is also known as Nitric Acid  

Explanation: and the process in making aqua fortis is THE OSTWALDS PROCESS

detailed explanation by me

ammonia is also used in this process, which is reacted with oxygen and water and a catalyst platinum.

HOPE THIS HELPSS!!!

7 0
3 years ago
9. A student is dissolving sugar in water. What can
pychu [463]

Answer:

D

Explanation:

Sugar will dissolve faster when you stir the solution quickly because the act of stirring increases kinetic energy which increases the temperature.

4 0
3 years ago
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