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kiruha [24]
3 years ago
6

What information is given in the MSDS for acetic acid?

Chemistry
1 answer:
Andreyy893 years ago
8 0

Answer: The reactivity of acetic acid with various chemicals (A)

Explanation: engenuity 2021

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Choose the products that complete the reaction. The chemical equation may not be balanced.
Alina [70]

Al2(SO4)3 + H2

Explanation:

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3 years ago
Read 2 more answers
Can anybody help please
romanna [79]

Answer:

Three hydrogen atoms

6 0
2 years ago
to find the mass of 3.2 moles of calcium for carbonate which of the following is used to calculate the amount
natka813 [3]
I believe it to be g/mol of Calcium carbonate
because to finde mass...u must have grams(g) as units....
it is the only one that have g as units 

as for the first answer the avogadros number gives u the number of atoms in  one mole of calcium carbonate....
the second one is based on ... At s.t.p one mole of gas occupies 22.4 dm³⇒to find volume 
6 0
3 years ago
Suppose that 0.1000 mole each of H2and I2are placed in a 1.000-L flask, stoppered, and the mixture is heated to 425oC. At equili
Katen [24]

<u>Answer:</u> The value of equilibrium constant for the given reaction is 56.61

<u>Explanation:</u>

We are given:

Initial moles of iodine gas = 0.100 moles

Initial moles of hydrogen gas = 0.100 moles

Volume of container = 1.00 L

Molarity of the solution is calculated by the equation:

\text{Molarity of solution}=\frac{\text{Number of moles}}{\text{Volume}}

\text{Molarity of iodine gas}=\frac{0.1mol}{1L}=0.1M

\text{Molarity of hydrogen gas}=\frac{0.1mol}{1L}=0.1M

Equilibrium concentration of iodine gas = 0.0210 M

The chemical equation for the reaction of iodine gas and hydrogen gas follows:

                         H_2+I_2\rightleftharpoons 2HI

<u>Initial:</u>                0.1    0.1

<u>At eqllm:</u>          0.1-x   0.1-x   2x

Evaluating the value of 'x'

\Rightarrow (0.1-x)=0.0210\\\\\Rightarrow x=0.079M

The expression of K_c for above equation follows:

K_c=\frac{[HI]^2}{[H_2][I_2]}

[HI]_{eq}=2x=(2\times 0.079)=0.158M

[H_2]_{eq}=(0.1-x)=(0.1-0.079)=0.0210M

[I_2]_{eq}=0.0210M

Putting values in above expression, we get:

K_c=\frac{(0.158)^2}{0.0210\times 0.0210}\\\\K_c=56.61

Hence, the value of equilibrium constant for the given reaction is 56.61

6 0
3 years ago
Position vs Time
photoshop1234 [79]

Answer:

The starting position of this object is 3 m.

The object is traveling at a velocity of 3 m/s

Explanation:

the graph begins at 3, and increases by 3 at each second

<em>plz mark me brainliest</em>. :)

8 0
3 years ago
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