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SCORPION-xisa [38]
3 years ago
13

How many Joules are there in 55 nutritional calories?

Chemistry
1 answer:
Sidana [21]3 years ago
8 0

Answer:

230.12

Explanation:

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A 30.5-g sample of water at 300. K is mixed with 48.5 g water at 350. K. Calculate the final temperature of the mixture assuming
ahrayia [7]

Answer:

sorry but i cant

Explanation:

8 0
3 years ago
The highest pressure ever produced in a laboratory setting was about 2.0 x 10 6 atm. If we have a
tigry1 [53]

Answer:

Volume = 72.7272

Explanation:

if only pressure and volume change, then we can do some simple math to find the answer.

2 x 10 ^ 6 times 1 x 10 ^-5 = 20

pressure and volume must equal 20

20 = 0.275 x volume

20 / 0.275 = new volume

I don't remember significant digits but your volume is 72.72727272 just repeated

8 0
3 years ago
8.310x10^2 – 7.210x10^1<br><br>[?]x10^[?]​
alisha [4.7K]

Answer:

7.589\times 10^{2}

Explanation:

The expression can be solved mathematically as follows:

1) 8.310\times 10^{2}-7.210\times 10^{1} Given

2) 8.310\times 10^{1+1} - 7.210\times 10^{1} Definition of sum

3) (8.310\times 10^{1})\times 10^{1}-7.210\times 10^{1} a^{m+n} = a^{m}\cdot a^{n}/Associative property

4) (8.310\times 10^{1}-7.210)\times 10^{1} Distributive property

5) (83.100-7.210)\times 10^{1} Multiplication

6) 75.89\times 10^{1} Subtraction.

7) (7.589\times 10^{1})\times 10^{1} Multiplication/Associative property

8) 7.589\times (10^{1}\times 10^{1}) Associative property

9) 7.589\times 10^{2} a^{m+n} = a^{m}\cdot a^{n}/Result

7 0
3 years ago
A 4.0 L container holds a sample of hydrogen gas at 306 K and 150 kPa. If the pressure increases to 300 kPa and the volume remai
riadik2000 [5.3K]

Answer:

612 K

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 306 K

Initial pressure (P₁) = 150 kPa

Final pressure (P₂) = 300 kPa

Volume = 4 L = constant

Final temperature (T₂) =?

Since the volume is constant, the final (i.e the new) temperature of the gas can be obtained as follow:

P₁ / T₁ = P₂ / T₂

150 / 306 = 300 / T₂

Cross multiply

150 × T₂ = 306 × 300

150 × T₂ = 91800

Divide both side by 150

T₂ = 91800 / 150

T₂ = 612 K

Thus, the new temperature of the gas is 612 K

4 0
3 years ago
Give the number of atoms of each type of sodium carbonate
Bad White [126]

Answer:What is the question

Explanation:

6 0
3 years ago
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