F_P + F_Q = M g
F_P = M g - F_Q
Torque, or moment of force:
∑ M_P = 0
∑ M_P = M g L - F_Q · 3 L
0 = M g L - 3 F_Q L / : L
0 = M g - 3 F_Q
3 F_Q = M g
F_Q = M g /3
Finally:
F_P = M g - M g/3
F_P = 4 M g / 3
A difference between the two forces is the fact that gravitation only attracts, while electrical forces attract when the electrical charges are opposite and repel if the charges are similar. Thus, gravitation is considered a monopole force, while electrostatics is a dipole force. Please mark me as a brainiest!!!
Answer:
![T=326.928K](https://tex.z-dn.net/?f=T%3D326.928K)
Explanation:
From the question we are told that:
Emissivity ![e=0.44](https://tex.z-dn.net/?f=e%3D0.44)
Absorptivity ![\alpha =0.3](https://tex.z-dn.net/?f=%5Calpha%20%3D0.3)
Rate of solar Radiation ![R=0.3](https://tex.z-dn.net/?f=R%3D0.3)
Generally the equation for Surface absorbed energy is mathematically given by
![E=\alpha R](https://tex.z-dn.net/?f=E%3D%5Calpha%20R)
![E=0.3*950](https://tex.z-dn.net/?f=E%3D0.3%2A950)
![E=285W/m^2](https://tex.z-dn.net/?f=E%3D285W%2Fm%5E2)
Generally the equation for Emitted Radiation is mathematically given by
![\mu=e(\sigmaT^4)](https://tex.z-dn.net/?f=%5Cmu%3De%28%5CsigmaT%5E4%29)
Where
T=Temperature
![\sigma=5.67*10^8Wm^{-2}K_{-4}](https://tex.z-dn.net/?f=%5Csigma%3D5.67%2A10%5E8Wm%5E%7B-2%7DK_%7B-4%7D)
Therefore
![\alpha*E=e \sigma T^4](https://tex.z-dn.net/?f=%5Calpha%2AE%3De%20%5Csigma%20T%5E4)
![0.3*(950)=0.44(5.67*10^-8)T^4](https://tex.z-dn.net/?f=0.3%2A%28950%29%3D0.44%285.67%2A10%5E-8%29T%5E4)
![T=326.928K](https://tex.z-dn.net/?f=T%3D326.928K)
When a ray of light passes from one medium to another it changes its path, this phenomenon of light is called the deviation of light.
To solve this problem we will apply the concepts related to energy conservation. We will start by defining the expressions of the electric potential energy for a given charge (and for the electron). With this we can apply the conservation of kinematic energy. Our values are given as
![V = 80000V](https://tex.z-dn.net/?f=V%20%3D%2080000V)
The potential energy:
![U = qV](https://tex.z-dn.net/?f=U%20%3D%20qV)
Here,
q = Charge
V = Voltage
Or specifically for an electron we can define it as,
![U_e = eV](https://tex.z-dn.net/?f=U_e%20%3D%20eV)
Here,
e = Charge of electron
V = Voltage
Applying the energy conservation equations we have that the kinetic energy must be equivalent to the electric potential energy,
![KE= U_e](https://tex.z-dn.net/?f=KE%3D%20U_e)
![\frac{1}{2}mv^2 = qV =e V](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dmv%5E2%20%3D%20qV%20%3De%20V)
Here
v = Velocity
m = Mass
Rearranging,
![v^2 = \frac{2eV}{m}](https://tex.z-dn.net/?f=v%5E2%20%3D%20%5Cfrac%7B2eV%7D%7Bm%7D)
Replacing,
![v^2 = \frac{2(1.6*10^{-19})(80000)}{9.1*10^{-31}}](https://tex.z-dn.net/?f=v%5E2%20%3D%20%5Cfrac%7B2%281.6%2A10%5E%7B-19%7D%29%2880000%29%7D%7B9.1%2A10%5E%7B-31%7D%7D)
![v= 2.81*10^{16}](https://tex.z-dn.net/?f=v%3D%202.81%2A10%5E%7B16%7D)
For each electron the velocity is,
![v = 1.68*10^8m/s](https://tex.z-dn.net/?f=v%20%3D%201.68%2A10%5E8m%2Fs)
Therefore the velocity of the electron is ![1.68*10^8m/s](https://tex.z-dn.net/?f=1.68%2A10%5E8m%2Fs)