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algol [13]
3 years ago
5

You are working in the lab, how many grams of solute you need to make 200.0 g of 3.4% of solution?

Chemistry
1 answer:
Goryan [66]3 years ago
6 0

Answer:

6.8g of solute are needed

Explanation:

Percent by mass, (w/w%) is defined as the mass of solute in 100g of solution. A solution that is 3.4% contains 3.4g of solute in 100g of solution. That means to make 200g of solution are required:

200g solution * (3.4g solute / 100g solution) = 6.8g of solute are needed

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For an object to sink
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3 years ago
PLEASE HELP ME!!! ASAP
shtirl [24]

Answer:

Theoretical yield of the reaction = 34 g

Excess reactant is hydrogen

Limiting reactant is nitrogen

Explanation:

Given there is 100 g of nitrogen and 100 g of hydrogen

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Number of moles of hydrogen = 100 ÷ 2 = 50

Reaction between nitrogen and hydrogen yields ammonia according to the following chemical equation

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From the above chemical equation for every mole of nitrogen that reacts, 3 moles of hydrogen will be required and 2 moles of ammonia will be formed

Now we have 3·57 moles of nitrogen and therefore we require 3 × 3·57 moles of hydrogen

⇒ We require 10·71 moles of hydrogen

But we have 50 moles of hydrogen

∴ Limiting reactant is nitrogen and excess reactant is hydrogen

From the balanced chemical equation the yield will be 2 × 3·57 moles of ammonia

Molecular weight of ammonia = 17 g

∴ Theoretical yield of the reaction = 2 × 3·57 × 17 = 121·38 g

5 0
3 years ago
The pKa of the α‑carboxyl group of serine is 2.21 , and the pKa of its α‑amino group is 9.15 . Calculate the average net charge
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Answer:

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  • Net charge in serine at pH equal to 8.30 is "0".
  • Structure of serine at pH equal to 8.30 has been shown below.

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What does 2Cl mean?​
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