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madreJ [45]
3 years ago
11

MANUFACTURING QUESTION PLEASE HELP​

Engineering
1 answer:
Nat2105 [25]3 years ago
3 0

Answer:

"He then pours the metal into a mold and allows it to solidify."

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(30 pts) A simply supported beam with a span L=20 ft and cross sectional dimensions: b=14 in; h=20 in; d=17.5 in. is reinforced
Nat2105 [25]

Answer:

Zx = 176In³

Explanation:

See attached image file

5 0
3 years ago
Planetary gears require the armature to be offset via a gear housing that holds the starter drive.
Yuri [45]

Answer: Due to the way that spur gears work, starters that use them require an offset armature, which is achieved by placing the starter drive in separate gear housing. In starters that use planetary gears, the gears can be contained in an in line drive-end housing.

Explanation: true

6 0
3 years ago
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Name two common fuel gases that can be used for oxyfuel cutting
zlopas [31]
Hi

Acetylene and propane

I hope this help you!
8 0
1 year ago
A supply fan is operating at 30000 cfm and 4 inch of water with an efficiency of 50%. (a) Calculate the fan power at the current
serg [7]

Answer:

The pressure and power of fan is 1.77 and 11.18 Hp respectively.

Explanation:

Given:

Discharge Q_{1}  = 30000 cfm

Pressure difference \Delta P = 4 inch

Efficiency \eta = 50\%

(A)

From the formula of fan power,

     P _{1}  = \frac{Q \Delta P}{6356 \eta}

     P_{1}  = \frac{30000 \times 4}{6356 \times 0.5}

     P_{1}  = 37.76 Hp

(B)

Fan power and pressure is given by,

We know that pressure difference is proportional to the square of discharge.

    \frac{\Delta p_{2} }{\Delta P_{1} } = (\frac{Q_{2} }{Q_{1} } ) ^{2}

   \Delta P_{2}  = (\frac{20000}{30000} ) \times 4

   \Delta P_{2} = 1.77

Fan power proportional to the cube of discharge.

       \frac{P_{2} }{P^{1} }  = (\frac{Q_{2} }{Q_{1} } )^{3}

       P_{2} =   \  (\frac{20000}{30000} ) ^{3} \times 37.76

       P_{2} = 11.18 Hp

Therefore, the pressure and power of fan is 1.77 and 11.18 Hp respectively.

5 0
3 years ago
Estimate horizontal and vertical tail sizes fo r a twin-turboprop regional transport with wing area of 40 m2, aspect ratio of 10
svetlana [45]

Answer: 0.2m sqr

Explanation:

A well behaved aircraft basically have a value of volume in horizontal and vertical area.

Volume in horizontal area (Vh) = 0.6

Volume in vertical area (Vv) = 0.05

Having known this, consider the relationship to find the vertical and horizontal tail sizes.

Vertical tail area (Sv)

Horizontal tail area (Sh)

Vh= (Sh × I) / S

Where,

I = moment

S= wing area

Sh= Horizontal tail area

Vh= Volume in horizontal area

0.6= Sh × 10/40

24= 10Sh

Sh= 24/10

Sh= 2.4 msqr

Horizontal tail area= 2.4m sqr

From the information above, we can calculate the vertical tail area.

Vertical tail area is calculated thus below:

Vv= (Sv× I) / S

Where

Vv= Volume in vertical area

Sv= Vertical tail area

I= Moment

S= Wing area

Therefore

Sv= (Vv × S) /I

Sv= (0.05×40)/10

Sv= 0.2msqr

In conclusion, the vertical tail size is 0.2msqr

7 0
3 years ago
Read 2 more answers
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