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KATRIN_1 [288]
3 years ago
6

A compound is composed of 13% carbon, 4.3% hydrogen, 30.4% nitrogen, and 52.2% oxygen. The mystery compound has a molar mass of

184 grams per mole. What is the molecular formula of the compound
Chemistry
1 answer:
vredina [299]3 years ago
8 0

Answer:

C₂H₈N₄O₆ is the molecular formula for the compound

Explanation:

Data from the problem:

13 g of C in 100 g of compound

4.3 g of H in 100 g of compound

30.4 g of N in 100 g of compound

52.2 g of O in 100 g of compound

Firstly we determine, the mass of each in 184 g of compound, which is 1 mol

(13 g / 100 g) . 184 g  = 24 g C

(4.3 g  / 100 g) . 184 g  = 7.91 g H ≅ 8 g H

(30.4 g / 100 g) . 184 g  = 56 g N

(52.2 g  / 100 g) . 184 g  = 96 g O

And now, we divide the mass by the molar mass of each to determine the moles:

24 g C / 12 g/mol = 2 mol C

8g H / 1 g/mol = 8 mol H

56 g N / 14 g/mol = 4 mol N

96 g O / 16 g/mol = 6 mol O

So the molecular formula of the compound is C₂H₈N₄O₆

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he balanced net ionic equation for precipitation of CaCO 3 when aqueous solutions of Na 2CO 3 and CaCl 2 are mixed is ________.
ale4655 [162]

Answer:

Net ionic equation: Ca^{2+}(aq.)+CO_{3}^{2-}(aq.)\rightarrow CaCO_{3}(s)

Explanation:

Reaction between Na_{2}CO_{3} and CaCl_{2} is an example of double decomposition reaction where each cations and anions of each salt exchange their partners during reaction to form CaCO_{3} and NaCl

CaCO_{3} is an insoluble salt. Hence precipitation of CaCO_{3} has been observed.

Molecular equation: Na_{2}CO_{3}(aq.)+CaCl_{2}(aq.)\rightarrow 2NaCl(aq.)+CaCO_{3}(s)

Total ionic equation:

2Na^{+}(aq.)+CO_{3}^{2-}(aq.)+Ca^{2+}(aq.)+2Cl^{-}(aq.)\rightarrow CaCO_{3}(s)+2Na^{+}(aq.)+2Cl^{-}(aq.)

Here Na^{+} and Na^{+} are spectator ions. Therefore they are eliminated from both side of total ionic equation to get net ionic equation.

Net ionic equation: Ca^{2+}(aq.)+CO_{3}^{2-}(aq.)\rightarrow CaCO_{3}(s)

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3 years ago
if each of the following represents an alkane, and a carbon atom is located at each vertex with the proper number of hydrogen at
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three carbon is the most reactive

The ending carbon atoms of an extended aliphatic chain can combine in organic chemistry to create a closed system or ring, which results in cycloalkanes. These substances are referred to as cyclic substances. Cyclopropane, cyclobutane, cyclopentane, among many more, are examples.

Since cyclopropane has rings in its structural arrangement, it is less stable than the other cycloalkanes mentioned above. The positional orientation of the atoms of cycloalkane compounds, which have a tendency to emit a very high and unfavorable energy, is known as the ring strain. The ring becomes unstable and reactive due to the release of heat energy that has been trapped in its bonds and molecules.

The smaller cycloalkanes are more significantly impacted by the ring strain in terms of their structural makeup and conformational behavior.

To know more about carbon atoms refer to brainly.com/question/23971871

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Which alkaline earth metal is part of the reaction process of photosynthesis answers?
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How many elements are there
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4 0
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(c) ammonium carbonate + lead nitrate ? Step-by-step solution Step 1 of 3 v Step 2 of 3 v Step 3 of 3 ^ c) The ions formed in so
kenny6666 [7]

<u>Answer:</u> The net ionic equation is written below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium carbonate and lead nitrate is given as:

(NH_4)_2CO_3(aq.)+Pb(NO_3)_2(aq.)\rightarrow PbCO_3(s)+2NH_4NO_3(aq.)

Ionic form of the above equation follows:

2NH_4^+(aq.)+CO_3^{2-}(aq.)+Pb^{2+}(aq.)+2NO_3^-(aq.)\rightarrow PbCO_3(s)+2NH_4^+(aq.)+2NO_3^-(aq.)

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

Pb^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow PbCO_3(s)

Hence, the net ionic equation is written above.

3 0
3 years ago
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