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3 years ago

WHAT TYPE OF MOON IS THIS WILL MARK AS BRAINLIEST :)

Physics

2 answers:

Liula [17]3 years ago

5 0

It is a waning Crescent moon

weqwewe [10]3 years ago

4 0

The answer is new moon. Hope this helps

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Which of these statements best proves that electromagnetic forces are weaker than strong nuclear forces? Neutrons do not repel o

MAVERICK [17]

Protons do not move out of the nucleus of atoms although they repel each other.

Remember that protons are particles with positive charge and they held together in the nucleus of the atom which is a tiny tiny region. As you know, like charges repel each other, which means that the protons exert a repulsion force.

8 0

3 years ago

Along some shorelines, incoming waves cause the water to simply rise and fall rather that form a surf zone. What does this tell

NARA [144]

Answer:

Explained

Explanation:

Along some shorelines, incoming waves cause the water to simply rise and fall and not form surfs because of the steepness of the shorelines. Long period waves wont form surfs at steep shores because of the breaking and unstability of waves. Wave breaks at the shallow waters. The breaking of the waves depends upon H/L ratio.

5 0

3 years ago

You have a radioactive sample with a half-life of 1 hour. At t = 1 hour, a Geiger counter measures its radiation at 40 counts/mi

Mama L [17]

Answer:

Explanation:

Given that, .

The half-life of a radioactive element is

t½ = 1 hr.

At the first hour, the radioactive element has 40 counts/minute

After 4 hours it has 5 counts/minute

So,

We want to filled the table.

0 hours, I.e at the start

40 counts/mins × 2 = 80 counts / mis

First half-life (first hour) is

40 counts/mins

Second half-life (second hour)

40 counts/mins × ½ = 20 counts/mins

Third half-life (third hour)

40 counts/mins × ¼ = 10 counts / mins

Fourth half life (fourth hour)

40 counts/mins × ⅛ = 5 counts / mins

So, the table is

Time........................Geiger Counter Rate

0 hours.................... 80 counts / minutes

1 hour........................ 40 counts / minutes

2 hours..................... 20 counts / minutes

3 hours..................... 10counts / minutes

4 hours...................... 5 counts / minute

6 0

3 years ago

A physics student tests the theory of projectile motion by leaping off a 225 meter tall building. She runs off the building hori

tamaranim1 [39]

In this item, we are given with the x-component of the velocity. The y-component is equal to 0 m/s. The time it takes for it to reach the volume can be related through the equation,

d = V₀t + 0.5gt²

Substituting the known values,

225 = (0 m/s)(t) + (0.5)(9.8)(t²)

Simplifying,

t = 6.776 s

To determine the distance of the student from the edge of the building, we multiply the x-component by the calculated time.

range = (12.5 m/s)(6.776 s)

range = 84.7 m

<em>Answer: 84.7 m</em>

4 0

3 years ago

Is the matching correct?

iragen [17]

Yes thats right :)

have a great day!!!

7 0

3 years ago