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Temka [501]
3 years ago
7

What are four things that are cycled in the environment?

Physics
2 answers:
kiruha [24]3 years ago
8 0

Answer:

Water , Carbon , Nitrogen , Phosphorus , Sulfur

Explanation:

alexandr1967 [171]3 years ago
4 0

Answer:

1.water 2.ricks 3.gas 4.ice

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PLEASE HELP! I'LL GIVE BRAINLEST​
DochEvi [55]

Answer:

1.62 m/s²

Explanation:

4 0
2 years ago
Please Help with this
Tasya [4]

Answer:

N = 3600 N

Explanation:

centripetal acceleration requirement is

ac = v²/r = 20²/50 = 8 m/s²

As the only available acceleration is gravity, centripetal acceleration must come from that,

This makes the "weight" that the road senses and must counteract

N = m(g - ac)

N = 2000(9.8 - 8)

N = 3600 N

3 0
3 years ago
(b) A Blu-ray laser has a power of 5 milliwatts (1 watt = 1 J s−1). How many photons of light are produced by the laser in 1 hou
worty [1.4K]

Answer:

The number of photons of light produced by the laser in 1 hour is

1 Photon / hour

Explanation:

Number of photons of light produced is given by

Number of photons = \frac{Power}{Energy}

From the question,

Power = 5 mW (milliwatts) = 5 × 10⁻³ W

Since 1 Watt = 1 Js⁻¹

Then, 5 × 10⁻³ W = 5 × 10⁻³ Js⁻¹

For the Energy,

As given from the question

Energy=(Power)x(time)

Time = 1 hour = (1 × 60 × 60) s = 3600 s

∴ Energy = 5 × 10⁻³ Js⁻¹ x 1 x 3600s

Energy =18.0 J

Now for the Number of photons produced,

Number of photons = \frac{Power}{Energy}

Power = 5 × 10⁻³ Js⁻¹ = 0.005 Js⁻¹

Number of photons = \frac{0.005}{18}

Number of photons = 2.78 × 10⁻⁴ Photons / sec

This is the number of photons produced in 1 second.

For the number of photons produced in 1 hour, we will multiply the result by 3600

(NOTE: 1 sec = \frac{1}{3600} hour)

Number of photons = 2.78 × 10⁻⁴ Photons / sec

= 2.78 × 10⁻⁴ × 3600 Photons / hour

= 1.0008 Photons / hour

≅ 1 Photon / hour

Hence, the number of photons of light produced by the laser in 1 hour is

1 Photon / hour

5 0
3 years ago
If 730-nm and 640-nm light passes through two slits 0.61 mm apart, how far apart are the second-order fringes for these two wave
Naddik [55]

Answer:

X2 - X2'=3.24×10⁻⁴m

Explanation:

Given Data

λ1=730nm=

λ2=640nm

d=0.61 mm

D=1.1 m

Distance of the second bright fringe from the central fringe is given by

Xn = = D x n x2 λ / d

X2 = 2 D λ1 / d

X2' = 2 D λ2 / d

Separation between the second bright fringes of the two wavelengths ( the separation between the second order fringes ) is ,

X2 - X2' = 2 D ( λ1 - λ2 ) / d

X2 - X2'= {2 x 1. 1 (730×10^-9 - 640×10^-9) }/ 0.61 x 10 ^-3

X2 - X2'=3.24×10⁻⁴m

7 0
3 years ago
If the forces acting on an object are balanced, what must be true about the motion of the object? (DOK 1, AKS 8b) A. It must be
dangina [55]

Answer:

D

Explanation:

If the forces on an object are balanced (or if there are no forces acting on it), this is what happens: a stationary object stays still a moving object continues to move at the same speed and in the same direction Remember that an object can be moving, even if there are no forces acting on it.

3 0
3 years ago
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