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stich3 [128]
3 years ago
11

The number of moles of hydrogen that are needed to produce .253 moles of water​

Chemistry
1 answer:
Brut [27]3 years ago
8 0

Answer:

454

Explanation:

j

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Identify the acid and conjugate base pair in the following equation:
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Answer:

hola no ablo inalgun moderador puede acabar a este otro este me borró respuesta que no debió borrar

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2 years ago
In which situation is no work considered to be done by a force?
Masja [62]

If the angle is either 0 or 180, that means that there is either negative or positive work, so A and D are not correct.

If the angle is 45, then there is still some work involved.

The only option where there is no work done by a force is B. when the angle is between the force and displacement is 90. 

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A 2.1−mL volume of seawater contains about 4.0 × 10−10 g of gold. The total volume of ocean water is about 1.5 × 1021 L. Calcula
Fiesta28 [93]

Answer:

Total worth of gold in the ocean = $5,840,000,000,000,000

Explanation:

As stated in the question above, 4.0 x 10^-10 g of gold was present in 2.1mL of ocean water.

Therefore, In 1 L of ocean water there will be,

(4.0 x 10^-10)/0.0021

= 1.9045 x 10^-7 g of gold per Liter of ocean water.

So in 1.5 x 10^-21 L of ocean water, there will be

(1.9045 x 10^-7) * (1.5 x 10^-21)

= 2.857 x 10^14 g of gold in the ocean.

1 gram of gold costs $20.44, that is 20.44 dollars/gram. The total cost of the gold present in the ocean is

20.44 * (2.857 x 10^14)

= $5,840,000,000,000,000

8 0
3 years ago
If the mass is 6.5g, and the volume is 25mL.. what is the density? PLEASE ANSWER ASAP
julia-pushkina [17]

Answer:

p = 260 kilogram/cubic meter

Explanation:

ρ =  \frac{m}{V} \\

  = \frac{6.5 g}{25mL}

=  0.26 gram/milliliter

=  260 kilogram/cubic meter

7 0
3 years ago
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