No, There are not likely to form in areas that experience a lot of erosion on a daily basis.
The octet rule states that atoms tend to form compounds in ways that give them eight valence electrons and thus the electron configuration of a noble gas
The electron configuration that represent an excited state for an atom of calcium is 2, 8, 7, 3.
Calcium atom has an atomic number of 20 and its electronic configuration is 2, 8, 8, 2. An atom is said to be in an excited state if it gains energy and move to an higher energy level. For the calcium atom given above, there are 20 electrons which are distributed into four shells. But in the excited state [option 3], one of the 8 electrons in the third shell gains energy and move to the fourth shell. Thus, the number of electrons in the third shell reduced by 1, while the number of electrons in the fourth shell increase by 1.
Answer:
[H⁺] = 1.30X10⁻⁴ M
Explanation:
the problem will be solved by using Nernst's equation, which is :
In the given equation
n = 2
Q = ![=\frac{[Zn^{+2}][p_{H2}]}{[H^{+}]^{2}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5BZn%5E%7B%2B2%7D%5D%5Bp_%7BH2%7D%5D%7D%7B%5BH%5E%7B%2B%7D%5D%5E%7B2%7D%7D)
Putting values
![0.53= 0.76 - \frac{0.0592}{n}log(\frac{1X1}{[H^{+}]^{2}})](https://tex.z-dn.net/?f=0.53%3D%200.76%20-%20%5Cfrac%7B0.0592%7D%7Bn%7Dlog%28%5Cfrac%7B1X1%7D%7B%5BH%5E%7B%2B%7D%5D%5E%7B2%7D%7D%29)
on calculating
[H⁺] = 1.30X10⁻⁴ M
Answer:
The correct option is;
The reaction pathway for the trials is different
Explanation:
The effect of a catalyst in a chemical reaction is to increase the rate of a reaction by changing the pathway or mechanism of the reaction and/or to lower the transition state's energy thereby lowering the activation energy of the reaction
The pathway of the reaction is changed by the catalyst by the formation of intermediate compounds by the catalyst which require lower activation energy to form the products than the original non-catalyzed reactants. In the process the catalyst is regenerated, thereby, not taking part in the reaction.
