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kari74 [83]
3 years ago
7

Calculate the mechanical energy TME______j of a 7.2 kg object moving at 2.4 m/ s and positioned 5.8m above the ground.

Physics
1 answer:
VladimirAG [237]3 years ago
7 0

Answer:

Mechanical energy = 429.984J

Explanation:

Given the following data;

Mass = 7.2kg

Velocity = 2.4m/s

Height = 5.8m

To find the mechanical energy;

Mechanical energy = kinetic energy + potential energy

First of all, we would determine the values of K.E and G.P.E

K.E = ½mv²

K.E = ½*7.2*2.4²

K.E = 3.6*5.76

K.E = 20.736 J

P.E = mgh

We know that acceleration due to gravity is equal to 9.8m/s²

P.E = 7.2*9.8*5.8

P.E = 409.248

Substituting the values into eqn 1, we have;

Mechanical energy = 20.736 + 409.248

Mechanical energy = 429.984J

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Calculate the average induced voltage between the tips of the wings of an airplane flying above East Lansing at a speed of 885 k
Yakvenalex [24]

Answer:

=0.855V

Explanation:

The induced voltage can be calculated using below expression

E =B x dA/dt

Where dA/dt = area

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speed = 885 km/h

speed = 885 x 10^3 m/hr

speed = 885 x 10^3/60 x60 m/s

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If The aircraft wing sweep out" an area

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dA/dt = 50.4 x 245.8

= 123388.32m^2/s

Then from the expression above

E =B x dA/dt substitute the values of each parameters, we have

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