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sasho [114]
3 years ago
8

What is the molar mass of a covalent compound if 0.486 g of it is dissolved in 25.0 ml of water and produces a freezing temperat

ure of -0.40 °c?
Chemistry
1 answer:
Semmy [17]3 years ago
3 0

Answer is: the molar mass of a covalent compound is 90.4 g/mol.

<span> m(compound) = 0.486 g.
m(water) = 25 mL </span>· 1 g/mL = 25 g ÷ 1000 g/kg = 0.025 kg.<span>
ΔT = 0°C - (-0.40°C) = 0.40°C.</span>

Kf(H₂O) = 1.86°C/m.

M(compound) = Kf · m(compound<span>) / m(water) · ΔT.
M</span>(compound)<span>= 1.86°C/m · 0.486 g / (0.025 kg · 0.4°C).
M</span>(compound) = 90.4 g/mol.

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A compound is known to consist solely of carbon, hydrogen, and chlorine. Through elemental
OleMash [197]

Answer:

the empirical (lowest raios) is

C2H4Cl    

Explanation:

A compound is known to consist solely of carbon, hydrogen, and chlorine. Through elemental analysis, it was determined that the compound is composed of 24.27% carbon.

What is the empirical formula of this compound?

the compound has ONLY C, H, and Cl

the % Cl  = 100% - 24.27% -4.03% = 71.7%

in 100 gm, there are 71.7 gm Cl, 24.27 gm C, and 4.03 gm H

the number of moles are Cl=71.7/70.91 =1.01= ~ 1

                                          C = 24.27/12.0 = 2.02 =~ 2

                                           H = 403/1.01 = 3.97 =~   4

so   the empirical (lowest raios) is

C2H4Cl      

                                 

                               

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2 years ago
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2. How many moles are in 8.30 x 1023 molecules of H2O?
daser333 [38]

Answer:

<h2>1.38 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.30 \times  {10}^{23} }{6.02 \times  {10}^{23} }  =  \frac{8.30}{6.02}  \\  = 1.3787 37...

We have the final answer as

<h3>1.38 moles</h3>

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3 years ago
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