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sasho [114]
3 years ago
8

What is the molar mass of a covalent compound if 0.486 g of it is dissolved in 25.0 ml of water and produces a freezing temperat

ure of -0.40 °c?
Chemistry
1 answer:
Semmy [17]3 years ago
3 0

Answer is: the molar mass of a covalent compound is 90.4 g/mol.

<span> m(compound) = 0.486 g.
m(water) = 25 mL </span>· 1 g/mL = 25 g ÷ 1000 g/kg = 0.025 kg.<span>
ΔT = 0°C - (-0.40°C) = 0.40°C.</span>

Kf(H₂O) = 1.86°C/m.

M(compound) = Kf · m(compound<span>) / m(water) · ΔT.
M</span>(compound)<span>= 1.86°C/m · 0.486 g / (0.025 kg · 0.4°C).
M</span>(compound) = 90.4 g/mol.

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Tpy6a [65]
Q=m(c∆t +heat of fusion + heat of evaporation)

m= 44g
c= 4.186 J/g.C
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5 0
3 years ago
The calvin cycle and the krebs are referred to as cycles of chemical reactions because they
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Answer:

The options are

a. occur inside organelles. b. start over continually. c. are part of the carbon cycle. d. allow energy to flow in ecosystems.

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A good example involves the existing Carbon dioxide and water reacting together to get converted into substance that could provide energy (ATP and NADH) such as Glucose.

8 0
3 years ago
How much carbon would be needed to make 8.8g of carbon dioxide?<br>​
PIT_PIT [208]
The calculation for such a question can be achieved via Avogadro hypothesis

We know molar mass of CO2 is 44g/mole which is the sum of atomic masses i.e; C and 2 oxygen atoms

Molar mass of CO2 =12(C)+2*16(O) = 44 g/mole will contain 6.023 ※10^23 CO2 molecules ..

44g/mole = 6.023 ※10^23 CO2 molecules

=> 1g = (6.023/44) ※10^23 CO2 molecules

==> 8.80g = 8.80(6.023÷44)10^23 = 1.2046 ※10^23 molecules of CO2….

Thus there r 1.2046 ※10^23 molecules of CO2 in 8.80g

if u need to calculate no. of carbon atoms then multiply result by 1 and if u need no of oxygen atoms in 8.80g of co2 then multiply the result by 2 ….
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Answer: 960 degrees celsius

Explanation:

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I believe the answer is "Bohr's model explains the chemical behavior of all atoms."

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3 years ago
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