Answer:
the correct option is B
Explanation:
The correct option is b, since if we reach pH 7, it means that the acid-base reaction is neutralized, therefore the base has been neutralized by an acid or vice versa, without taking into account the proteins or the amounts of both components .
<h3><u>Answer;</u></h3>
= 11,460 years
<h3><u>Explanation;</u></h3>
- <em><u>The half life of Carbon-14 is 5,730 years
. Half life is the time taken by a radioactive material to decay by half of its original mass. Therefore, it would take a time of 5730 years for a sample of 100 g of carbon-14 to decay to 50 grams</u></em>
<em>The initial amount of carbon-14 in this case was 1 whole; thus; </em>
<em>1 → 1/2 →1/4</em>
<em>To contain 1/4 of the value, 2 half-lives have passed.
</em>
<em>But, 1 half life = 5,730 years</em>
<em>Therefore; The artifact is is therefore: 2 x 5,730
</em>
<em> = 11,460 years </em>
Answer:
1) Monochrome
2) Monocot
3) Monosaccharide
4) Monounsaturated
5) Monoxide
Explanation:
The prefix mono or mon is of Greek origin and it means single, lone or one.
From the meaning of the words we can tell that they have something in common:
1) Monochrome: This refers to an artwork, a painting or drawing that has just one color.
2) Monocot: This is a type of flowering plant that has a single embryo and a single cotyledon.
3) Monosaccharide: This is a type of simple sugar that contains one sugar unit that cannot be split.
4) Monounsaturated: This refers to a molecule that contains one double or triple bond.
5) Monoxide: This refers to a form of oxide that contains only one oxygen atom.
From the definitions above, all the words mean having only one or a single item.
That is what they have in common.
Answer:

Explanation:
Ba(OH)₂ + 2HCl ⟶ BaCl₂ + H₂O
V/mL: 249
c/mol·L⁻¹: 0.0443 0.285
1. Calculate the moles of Ba(OH)₂

2. Calculate the moles of HCl
The molar ratio is 2 mol HCl:1 mol Ba(OH)₂

3. Calculate the volume of HCl

Mass<span> is the amount of matter in an object. Move to a different planet and an object's weight will change, but its </span>mass<span> will be the same. </span>