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guapka [62]
3 years ago
6

Mount St. Helens is a volcano that erupted with great force in 1980. Which phrase best describes this eruption?

Chemistry
2 answers:
aksik [14]3 years ago
6 0

Answer:

high-viscosity magma

Explanation:

High viscosity lavas flow slowly and typically cover small areas. In contrast, low viscosity magmas flow more rapidly and form lava flows that cover thousands of square kilometers.

AleksAgata [21]3 years ago
5 0

Answer:The best phrase which supports the eruption would be high-viscosity magma lava broken into fragments.

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Identify each of the atomic models described here. Atoms are indivisible spheres. plum pudding model Dalton model Bohr model
mamaluj [8]

Atoms are indivisible spheres-Dalton model

John Dalton was the first to propose a theory to describe matter. As per Dalton's model, all matter is composed of atoms which resemble tiny 'ball-like' structures that are indivisible.

7 0
3 years ago
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Calculate the density from the following information: A red block had a mass of 15.7 g. It was placed into a graduated cylinder
matrenka [14]

Answer:

Density should be 8.5

Explanation:

When you subtract 17.2-10.0 for water displacement you get 7.2 which is the volume and you divide it by 15.7 so your equation will be 15.7/7.2 = 8.5

4 0
3 years ago
How many milliliters of 0.125 M FeCl3 are needed to react with an excess of Na2S to produce 3.75 g of Fe2S3 if the percent yield
Katyanochek1 [597]

Answer:

0.912 mL

Explanation:

3 Na2S(aq) + 2 FeCl3(aq) → Fe2S3(s) + 6 NaCl(aq)

FeCl3 is the limiting reactant.

Number of moles of iron III sulphide produced= 3.75g/87.92 g/mol = 0.043 moles

Hence actual yield of Iron III sulphide = 0.043 moles

Theoretical yield of Iron III sulphide = actual yield ×100%/ %yield

Theoretical yield of iron III sulphide= 0.043 ×100/75 = 0.057 moles of Iron III sulphide

From the reaction equation,

2moles of iron III chloride produced 1 mole of iron III sulphide

x moles of iron III chloride, will produce 0.057 of iron III sulphide

x= 2× 0.057= 0.114 moles of iron III chloride

But

Volume= number of moles/ concentration

Volume= 0.114/0.125

Volume= 0.912 mL

4 0
3 years ago
Calculate the whole-number ratio of staggered to eclipsed conformers that are present at room temperature. Use the Actual G˚ bar
natka813 [3]

Answer:

The ratio of staggered to eclipsed conformers is 134

Explanation:

It is possible to determine the ratio of staggered to eclipsed conformers of a reactant, using the equilibrium:

Staggered ⇄ Eclipsed

Keq = [Eclipsed] / [Staggered]

That means Keq is equal to the ratio we need to find:

Using:

G˚= -RTln Keq

<em>Where G° = -12133.6J/mol</em>

<em>R is gas constant: 8.314J/molK</em>

<em>T is absolute temperature: 298K</em>

<em />

-12133.6J/mol= -8.314J/molK*298K ln Keq

4.8974 = ln Keq

134 = Keq = [Eclipsed] / [Staggered]

<h3>The ratio of staggered to eclipsed conformers is 134</h3>
3 0
2 years ago
Examine the reaction equation. CH4 + O2 →H2O + CO2 What coefficients will balance the equation? A) 2, 3, 2, 2 B) 1, 3, 2, 1 C) 1
kiruha [24]

Answer:

B

Explanation:

CH4 + O2 →H2O + CO2

Left side

C = 1

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O = 2

Right side

C = 1

H = 2

O = 3

So find common denominator in this case would be 6 O

CH4 + 3O2 →2H2O + CO2

Left side

C = 1

H = 4

O = 6

Right side

C = 1

H = 4

O = 6

3 0
3 years ago
Read 2 more answers
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