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-BARSIC- [3]
3 years ago
8

The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this

information?
a. They are in the same group because they have similar atomic masses, but they are in different periods because they have different chemical properties.

b. They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

c. They are in the same group because their atomic numbers are each multiples of four, but they are in different periods because they have different chemical properties.

d. They are in the same group because they have similar atomic masses, but they are in different periods because they have very different atomic numbers.
Chemistry
2 answers:
Cloud [144]3 years ago
8 0
The answer is b) similar chemical properties but very different atomic numbers
SSSSS [86.1K]3 years ago
4 0

Answer:

B: They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

Explanation:

I took the Unit test on EDG and I got it correct

Pls mark me brainliest

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The gram-formula mass of NO2 is defined as the mass of
ch4aika [34]
The correct answer is (1) one mole of NO2.

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3 years ago
Read 2 more answers
Which ecosystem is more likely to become unstable one with many kinds of plants and animals or one with few kinds?
Art [367]

Answer:

One with a few kinds is more likely to become unstable.

Explanation:

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5 0
2 years ago
How many grams are in 1 mole of Ar?
Ilia_Sergeevich [38]

Answer: 39.948 grams

Explanation:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Ar, or 39.948 grams

3 0
3 years ago
A reaction of 41.9 g of Na and 30.3 g of Br2 yields 36.4 g of NaBr . What is the percent yield?
Licemer1 [7]

Answer: The percent yield is, 93.4%

Explanation:

First we have to calculate the moles of Na.

\text{Moles of Na}=\frac{\text{Mass of Na}}{\text{Molar mass of Na}}=\frac{41.9g}{23g/mole}=1.82moles

Now we have to calculate the moles of Br_2

{\text{Moles of}Br_2} = \frac{\text{Mass of }Br_2 }{\text{Molar mass of} Br_2} =\frac{30.3g}{160g/mole}=0.189moles

{\text{Moles of } NaBr} = \frac{\text{Mass of } NaBr }{\text{Molar mass of } NaBr} =\frac{36.4g}{103g/mole}=0.353moles

The balanced chemical reaction is,

2Na(s)+Br_2(g)\rightarrow 2NaBr

As, 1 mole of bromine react with = 2 moles of Sodium

So, 0.189 moles of bromine react with = \frac{2}{1}\times 0.189=0.378 moles of Sodium

Thus bromine is the limiting reagent as it limits the formation of product and Na is the excess reagent.

As, 1 mole of bromine give = 2 moles of Sodium bromide

So, 0.189 moles of bromine give = \frac{2}{1}\times 0.189=0.378 moles of Sodium bromide

Now we have to calculate the percent yield of reaction

\%\text{ yield}=\frac{\text{Actual yield}}{\text{Theoretical yield}}\times 100=\frac{0.353 mol}{0.378}\times 100=93.4\%

Therefore, the percent yield is, 93.4%

3 0
3 years ago
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