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-BARSIC- [3]
3 years ago
8

The atomic number of beryllium (Be) is 4, and the atomic number of barium (Ba) is 56. Which comparison is best supported by this

information?
a. They are in the same group because they have similar atomic masses, but they are in different periods because they have different chemical properties.

b. They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

c. They are in the same group because their atomic numbers are each multiples of four, but they are in different periods because they have different chemical properties.

d. They are in the same group because they have similar atomic masses, but they are in different periods because they have very different atomic numbers.
Chemistry
2 answers:
Cloud [144]3 years ago
8 0
The answer is b) similar chemical properties but very different atomic numbers
SSSSS [86.1K]3 years ago
4 0

Answer:

B: They are in the same group because they have similar chemical properties, but they are in different periods because they have very different atomic numbers.

Explanation:

I took the Unit test on EDG and I got it correct

Pls mark me brainliest

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2 years ago
If you have 5.2 moles of Na and excess CI2 how many moles of NaCI will be produced 2Na+CI2->2NaCI
sladkih [1.3K]

Answer:

5.2moles of NaCl

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From the equation,

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5 0
3 years ago
A compound made of elements A and B, has a cubic unit cell. There is an A atom at each corner of the cube and an A atom at the c
Lorico [155]

Answer:

A₅B₄

Explanation:

Since we have one atom of element A at the center of each face of the unit cell, since the unit cell is a cubic cell, we have 6 faces. Since the atom on the face of the unit cell is shared with another cell, we have half of it in the unit cell is shared So, the number of atoms per face is 1/2 atom/face × 6 faces = 4 atoms on the faces of the unit cell.

Also, we have 1 atom at each corner of the cubic unit cell. Since there are 8 corner in the cubic unit cell. Also, each atom at the corner is shared with 8 unit cells, so we have 1/8 atom per corner. So, the number of atoms per unit cell is 1/8 atom/corner × 8 corners = 1 atoms at the corners of the unit cell.

So, in total we have 4 + 1 = 5 atoms of element A in the unit cell.

Also, there are 4 atoms of element B in the unit cell.

So, the ratio of atoms of element A to element B is 5 : 4.

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So, the empirical formula of the compound containing elements A and B is A₅B₄

5 0
2 years ago
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